Selected values of the twice-differentiable function h and its first and second derivatives are given in the table above. What i
s the value of ∫41xh′′(x)ⅆx ?.
1 answer:
Answer:
Step-by-step explanation:
∫41 xh''(x)dx=41[x∫h''(x)dx-∫{1∫h''(x)dx}dx]+c
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Step-by-step explanation:
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Mode: 7
I believe this is correct.
