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Grace [21]
4 years ago
9

Find the range of the function. f(x) = (x - 2)2 + 2

Mathematics
2 answers:
sergiy2304 [10]4 years ago
7 0
Y>=2 is the answer yayayay
Aliun [14]4 years ago
5 0
[2,INFINITY SIGN)
{y|y greater than and equal to 2}

i hope it helps

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In the triangle below, what is the length of the side opposite the 30° angle? Picture and answers in attachment.
Alex17521 [72]

Answer:

The answer to this question is B.

8 0
4 years ago
Enrique charges $5 for every 1/5 hour he spends walking dogs. In the morning he walks buttons for 2/5 hour, Bruno for 1/5 hour,
VikaD [51]
Two hours and twelve minutes
60/5 = 12
12*2+12+12*3+12*4+12=
24+12+36+48+12=132
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two hours and twelve minutes
4 0
3 years ago
B = {(0.5k–5, 10), (k+7, 4)} solve for k
Paul [167]

Answer:

The chosen topic is not meant for use with this type of problem. Try the examples below.

√x+2=3

−4+y=3y+4(y−3)

2+|3x|=2+3

4 0
2 years ago
If Fred made $350 more than Jamie last month and Jamie made twice as much as Karl while together the three of them made $19,230,
icang [17]

As a teacher I have had students struggle with these type of questions... so let me explain how it works, I WILL NOT be giving students answers unless they figure it out...

multiply 365 × 0.75= your answer

4 0
3 years ago
A company offers a raffle whose grand prize is a $35,000 new car. Additional prizes are a $1,100 television and $600 computer. T
anastassius [24]

Answer:

-$ 10.13

Step-by-step explanation:

Given,

The cost price of each ticket = $ 22,

So, the value of each ticket other than price ticket = - $ 22, ( negative sign shows loss,i.e. if we don't get the price we will have the loss of $ 22 )

Now, there are 3 tickets in which first is of $35,000 price, second is of $1,100 and third is of $ 600,

So, the value of first ticket = 35000 - 22 = $ 34978,

Value of second ticket = 1100 - 22 = $ 1078,

Value of third ticket = 600 - 22 = $ 578,

Also,

\text{Probability}=\frac{\text{Favourable outcome}}{\text{Total outcome}}

Hence, by the above information we can make a table for the given situation,

Number           2997               1                    1                     1        

Price               -$ 22               $ 34978        $ 1078           $ 578

Probability       2997/3000      1/3000         1/3000           1/3000

Therefore, the expected value of a ticket

=-22\times \frac{2997}{3000}+34978\times \frac{1}{3000}+578\times \frac{1}{3000}

=-$10.126

≈ - $ 10.13

5 0
3 years ago
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