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Svetach [21]
3 years ago
6

127/4 + 62/3 × 24/6 solve this fraction by BODMAS

Mathematics
1 answer:
Arisa [49]3 years ago
3 0

Answer:

The correct solution is "114.39".

Step-by-step explanation:

The given expression is:

⇒ \frac{127}{4} +\frac{62}{3}\times \frac{24}{6}

On solving the above expression with the help of BODMAS rule, we get

Firstly we will have to apply division, we get

=  31.75+20.66\times 4

Now we will have to apply multiplication, we get

=  31.75+82.64

On adding, we get

=  114.39

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A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us
amm1812

Answer:

Given:

Sham: n= 20,     x=0.44,   s=1.24,

Magnet:n= 20,  x =0.49,   s= 0.95

For Sham:

Sample size, n = 20

Sample mean = 0.44

Standard deviation = 1.24

For Magnet:

Sample size = 20

Sample mean = 0.49

Standard deviation = 0.95

The null and alternative hypotheses:

H0: s1²=s2²

H1: s1² ≠ s2²

a) To find the test statistics, use the formula:

\frac{s1^2}{s2^2}

\frac{1.24^2}{0.95^2} = \frac{1.5376}{0.9025} = 1.7037

Test statistics = 1.7037

b) P-value:

Sham: degrees of freedom = n - 1 = 20 - 1 = 19

Magnet: degrees of freedom = n - 1 = 20 - 1 = 19

The critical values:

[Za/2, df1, df2)], [(1 - Za/2), df1, df2]

f[0.05/2, 19, 19], f[(1 - 0.05/2), 19, 19]

f[0.025, 19, 19], f[0.975, 19, 19]

(2.526, 0.3958)

The rejection region:

Reject H0, if  F < 0.3958 or if F > 2.526

c) Conclusion:

Since the critical values of test statistic is between (0.3958 < 1.7037 < 2.526), we fail to reject null hypothesis H0.

There is insufficient evidence to to support the claim that those given a sham treatment have reductions that vary more than those treated with magnets

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3 years ago
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\\ \sf\dashrightarrow x^3-y^3+x^2+y^2+3

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