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horrorfan [7]
3 years ago
7

You have a closed tank of air that holds 3.0L at a pressure of 203kP and temperature of 273K. When the tank and the air are heat

ed to 323K what is the pressure if the volume remains constant?
Chemistry
2 answers:
Dmitriy789 [7]3 years ago
6 0
The answer is 244.200244

Hope this helps!!
~Kiwi
topjm [15]3 years ago
5 0
So. .The first thing we will want to do is <span>p1/v1t1 = p2/v2t2. We have to understand this formula. Your correct answer would be </span>\boxed{244.200244}

Hope this helps.

~Jurgen
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Answer:

M_{K^+}=4.0M \\\\M_{SO_4^{2-}}=2.0M

Explanation:

Hello!

In this case, since the molarity of a solution is defined as the moles of solute divided by the volume of solution liters, given the mass of potassium sulfate, we can compute the moles by using its molar mass (174.24 g/mol):

n_{K_2SO_4}=87gK_2SO_4*\frac{1molK_2SO_4}{174.27gK_2SO_4} =0.50molK_2SO_4

Thus, since one mole of potassium sulfate has two moles of potassium ions (K₂) and one mole of sulfate ions, we can compute the moles of each ion as shown below:

n_{K^+}=0.50molK_2SO_4*\frac{2molK^+}{1molK_2SO_4}=1.0molK^+\\\\ n_{SO_4^{2-}}=0.50molK_2SO_4*\frac{1molSO_4^{2-}}{1molK_2SO_4}=0.50molSO_4^{2-}\\

In such a way, the molarity of each ion turns out:

M_{K^+}=\frac{1.0mol}{0.250L}=4.0M \\\\M_{SO_4^{2-}}=\frac{0.5mol}{0.250L}=2.0M

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