<span>Igneous
rocks are those rocks that were formed through cooling and solidifying the
molten materials. The best example for igneous rock is solid volcanic java.
Lava are liquid that comes from a volcano, but once it is dried and solidify,
it becomes a rock and called igneous rock.
Another example is the granite and basalt. And according to research igneous
rock comes from the latin word ignis which means fire. Thus this says it all.
From a liquid becomes a rock.
</span>
Answer:
6.022×10²² molecules
Explanation:
Given data:
Volume of nitrogen = 224 L
Pressure = standard = 1 atm
Temperature = standard = 273 K
Number of molecules = ?
Solution:
PV = nRT
1 atm × 224 L = n × 0.0821 atm.L/mol.K × 273 K
224 atm.L = n ×22.41 atm.L/mol
n = 224 atm.L/22.41 atm.L/mol
n = 10 mol
1 mole contain 6.022×10²³ molecules
10 mol×6.022×10²³ molecules/ 1 mol
60.22×10²³ molecules
6.022×10²² molecules
Answer:
A. She can run the same distance in a shorter amount of time.
Explanation:
Speed can be computed with the formula:

Where:
v = speed
d = distance
t = time
So if you look at the formula, distance there tells you how far an object has traveled, and the time tells us how long it took to cover that distance. As you can see, speed and time are <u>inversely proportional. </u>This means that as one goes up, the other goes down. So if we reduce time travelling a certain distance, the speed increases.
We are given the molar concentration of an aqueous solution of weak acid and the pH ofthe solution, and we are asked to determine the value of Ka for the acid.
The first step in solving any equilibrium problem is to write the equation for the equilibriumreaction. The ionization of benzoic acid can be written as seen in the attached image (1).
The equilibrium-constant expression is the equation number (2)
From the measured pH, we can calculate pH as seen in equation (3)
To determine the concentrations of the species involved in the equilibrium, we imagine that thesolution is initially 0.10 M in HCOOH molecules. We then consider the ionization of the acidinto H+ and HCOO-. For each HCOOH molecule that ionizes, one H+ ion and one HCOO- ionare produced in solution. Because the pH measurement indicates that [H+] = 1x 10^-4 M atequilibrium, we can construct the following table as seen in the equation number (4)
To find the value of Ka, please see equation (5):
We can now insert the equilibrium concentrations into the expression for Ka as seen in equation (6)
Therefore, 2.58x10^-4 M is the concentration of benzoic acid to have a pH of 4.0