Answer:
The answer to your question is maybe letter D, but the last oxygen needs a number 6.
Explanation:
The empirical formula gives the actual elements that form part of a molecule but not the total numbers.
The molecular formula gives the total number of atoms of each element in a molecule.
We must factor the molecular formula to know if a formula is the empirical formula of that.
A. CH₄ C₂H₆ = 2(CH₃) these are not empirical molecular formulas
B. CH₂O C₄H₆O these are not empirical-molecular formulas
C. O₂ O₃ these are not empirical-molecular formulas
D. C₃H₄O₃ C₆H₈O these are not empirical-molecular formulas
the last oxygen needs a number 6 to be
the answer.
The partial pressure is the amount of linguistic compound there is which makes the lagitude of the element 64.663
15.63 mol. You need 15.63 mol HgO to produce 250.0 g O_2.
<em>Step 1</em>. Convert <em>grams of O_2 to moles of O_2</em>
Moles of O_2 = 250.0 g O_2 × (1 mol O_2/32.00 g O_2) = 7.8125 mol O_2
<em>Step 2</em>. Use the molar ratio of HgO:O_2 to convert <em>moles of O_2 to moles of HgO
</em>
Moles of HgO = 0.8885 mol O_2 × (2 mol HgO/1 mol O_2) = <em>15.63 mol HgO</em>
Would it be lack of water and food?
