Answer:
$12,137.39
Step-by-step explanation:
Use the Compound Amount formula:
A = P (1 + r/n)^(nt), where r is the interest rate as a decimal fraction, n is the number of times the interest is compounded each year, and t is the number of years.
Here, A = $9000(1 + 0.075/12)^(12*4), or
= $9000(1.3486) = $12,137.39
Sally has 600 ml of drink
Karen has 600 ml of lime juice
When it is mixed at a ratio of 2:7:3 . . .pineapple:orange:lime (respectively) . . this means . . . there are a total of 2 + 7 + 3 parts = 12 parts . . and each part individually is as follows:
pineapple = 2/12
orange = 7/12
lime = 3/12
Sally has 12 parts = 600 ml of drink
. . pineapple = 2/12*600ml = 100 ml pineapple
. . orange = 7/12*600ml = 350 ml orange
. . lime = 3/12*600ml = 150 ml lime
We know Karen has 600 ml of lime juice and if that is 3/12 of the total, then 600*12/3 = the total drink = 2400 ml of drink
Karen has 12 parts = 2400 ml of drink
. . pineapple = 2/12*2400ml = 400 ml pineapple
. . orange = 7/12*2400ml = 1400 ml orange
. . lime = 3/12*2400ml = 150 ml lime
Thus . . . (for Karen) . . .
<u><em>A = 2400 ml of drink</em></u>
<u><em>B = 400 ml of orange juice</em></u>
<u><em>C = 1400 ml of pineapple juice</em></u>
Answer:
what do you mean
Step-by-step explanation:
what do you mean
Answer:
64 crates
Step-by-step explanation:
Smaller Cube Side Length = 2 1/2 feet, or, 2.5 feet
Larger Container (Cube) Side Length = 10 feet
We find volume of larger container and find volume of small crates. We divide the large volume by volume of each crate. This will give us number of crates we can fit.
Volume of Cube = x^3
Where x is the side length of the cube
Now,
Small Crate Volume = (2.5)^3 = 15.625 cubic feet
Large Container Volume = 10^3 = 1000 cubic feet
Number of crates that would fit = 1000/15.625 = 64
So, 64 crates will fit in the largest shipping container
Step-by-step explanation:
y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1
dy/dx = 12√x
Arc length is:
s = ∫ ds
s = ∫₀¹ √(1 + (dy/dx)²) dx
s = ∫₀¹ √(1 + (12√x)²) dx
s = ∫₀¹ √(1 + 144x) dx
If u = 1 + 144x, then du = 144 dx.
s = 1/144 ∫ √u du
s = 1/144 (⅔ u^(³/₂))
s = 1/216 u^(³/₂)
Substitute back:
s = 1/216 (1 + 144x)^(³/₂)
Evaluate between x=0 and x=1.
s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]
s = 1/216 (145)^(³/₂) − 1/216
s = (145√145 − 1) / 216
