The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:
where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:
Hence, the half life of the sample of phosphorus-32 is
B I think if I’m wrong I sooooo sorry
You start by subtracting: 16000-1200= 14800
Then you divide 14800 by how many feet the plane rises per minute
14800/945=16 minutes
The answer is 16 minutes
Answer:
15 chocolate chip
Step-by-step explanation:
1/4 of 20 is 5
this means there are 5 peanut butter cookies.
so 20-5= 15
this means there are 15 chocolate chip cookies
<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>!</em>
Answer:
25
Step-by-step explanation:
the question basically translates to
160% x n =40
a little trick with percents I use is that the word "of" always means multiplication.
n=40/160%=25
