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Dvinal [7]
2 years ago
6

I need to know how to find the mean for 77,82,87,85,32,78?

Mathematics
2 answers:
Maru [420]2 years ago
8 0

The answer is 73.5. Just add all the numbers and divided by how many numbers there are. So you would add all the numbers and then divided by 6 since there are 6 numbers.

lys-0071 [83]2 years ago
6 0

Answer:

73.5

Step-by-step explanation:

To find the mean, sum the data and divide by the amount of data

mean = \frac{77+82+87+85+32+78}{6}

          = \frac{441}{6} = 73.5

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Amiraneli [1.4K]

Answer:

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Step-by-step explanation:

like terms can be add or subtract

8 0
3 years ago
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In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that
attashe74 [19]

Answer:

(a) The probability of more than one death in a corps in a year is 0.1252.

(b) The probability of no deaths in a corps over 7 years is 0.0130.

Step-by-step explanation:

Let <em>X</em> = number of soldiers killed by horse kicks in 1 year.

The random variable X\sim Poisson(\lambda = 0.62).

The probability function of a Poisson distribution is:

P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...

(a)

Compute the probability of more than one death in a corps in a year as follows:

P (X > 1) = 1 - P (X ≤ 1)

             = 1 - P (X = 0) - P (X = 1)

             =1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252

Thus, the probability of more than one death in a corps in a year is 0.1252.

(b)

The average deaths over 7 year period is: \lambda=7\times0.62=4.34

Compute the probability of no deaths in a corps over 7 years as follows:

P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130

Thus, the probability of no deaths in a corps over 7 years is 0.0130.

6 0
2 years ago
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nataly862011 [7]

Answer:

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Step-by-step explanation:

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2% = 0.20 and so on

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(sorry if this is wrong)

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tigry1 [53]

Answer:

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Step-by-step explanation:

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Than begin crossing the numbers out

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Polynomial Expression.

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