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Nostrana [21]
3 years ago
6

Which exponential equation is equivalent to this logarithmic equation log x5 + log x12 =7

Mathematics
1 answer:
trapecia [35]3 years ago
5 0

Answer:

x⁷ = 60

Step-by-step explanation:

<u>Given</u><u> </u><u>:</u><u>-</u><u> </u>

  • log x⁵ + log x ¹² = 7 .

<u>To </u><u>Find</u><u> </u><u>:</u><u>-</u><u> </u>

  • The expotential equation .

<u>Solution</u><u> </u><u>:</u><u>-</u><u> </u>

Given logarithmic equation is ,

⇒ log x⁵ + log x ¹² = 7

⇒ log x ⁵ * ¹² = 7 [ log aⁿ + log aⁿ' = log aⁿ * ⁿ' ]

⇒log x ⁶⁰ = 7

In expotential form we can write it as ,

⇒ x⁷ = 60

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If m&lt;BEG = (19x + 3)° and m&lt;EGC = (m&lt;GCB + 4x)°, which of the following statements is true about quadrilateral BEGC? Se
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Answer:

The sum of all exterior angles of BEGC is equal to 360° ⇒ answer F only

Step-by-step explanation:

* Lets revise some facts about the quadrilateral

- Quadrilateral is a polygon of 4 sides

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- The sum of measures of the exterior angles of any quadrilateral is 360°

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∵ m∠BEG = (19x + 3)°

∵ m∠EGC = (m∠GCB + 4x)°

∵ The sum of the measures of its interior angles is 360°

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∴ 23x + 2m∠GCB + m∠CBE = 375

∵ The sum of measures of the exterior angles of any quadrilateral is 360°

∴ The statement in answer F is only true

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Step-by-step explanation:

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