Answer is <u>6|x+2|+2</u>
Please check the attached image of answer to clear the doubt.
<em>By </em><em>Benjemin</em><em> </em>☺️
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative

2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function

3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
<span>If you would like to know in which step did the student first make
an error, you can find this using the following steps:
y = 4 - 2z
4y = 2 - 4z
________________
-4(y) = -4(4 - 2z)
</span>4y = 2 - 4z<span>
________________
-4y = -16 + 8z ... Step 2
</span><span>4y = 2 - 4z</span><span>
________________
0 = -16 + 8z + 2 - 4z</span>
<span>16 - 2 = 4z</span>
<span>14 = 4z</span>
<span>z = 14/4 = 7/2</span>
<span>
The correct result would be: Student made an error in Step 2.</span>
Flip over the second fraction
2 3/5= 13/5 ( Multiply the whole number with the denominator, 2*5=10 then add the numerator 10+3=13
-3 3/4= -15/4
13/5 * -4/15= -52/75
Answer :-52/75
Answer:
r=28
Step-by-step explanation:
36/42 = 24/r (determine the defined range)
36/42 = 24/r , r ≠ 0 ( Reduce the fraction)
6/7 = 24/r (cross multiply)
6x = 168 ( divide both sides)
r=28 , r ≠ 0