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dimulka [17.4K]
2 years ago
15

Factor 3a^2+6ab-24b^2

Mathematics
1 answer:
Monica [59]2 years ago
7 0
(3a²+6ab-24²)= 3a(a+2b)x(4b)
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Nick, Paul and krutika share £80 in a ratio 1:1:2 how much money does each person get
pychu [463]

Answer:

Step-by-step explanation:

x + x + 2x = 80

4x =80

X = 20

Nick = 20

Paul = 20

Krutika = 40

4 0
3 years ago
melissa can earn $18 each time she cuts grass. if she cuts the grass x times, write an expression that shows how much she will e
Alborosie

18x

Simple as that. 18 times however many times she cuts the grass

7 0
2 years ago
Explain solving Slope
xeze [42]

ratio of vertical change between 2 points

5 0
2 years ago
Jake has two pet guinea pigs named fluffy and scruffy. Fluffy is8 1/8 inches long. Scruffy is 10 1/4 inches long. How much longe
miss Akunina [59]

Answer:

Scruffy is 2\frac{1}{8} inches longer than Fluffy.

Step-by-step explanation:

Length of Scruffy = 10\frac{1}{4} inches

Length of Fluffy = 8\frac{1}{8} inches

We have to calculate how much Scruffy is longer than Fluffy.

Difference of their lengths = 10\frac{1}{4}-8\frac{1}{8}

                                            = (10 - 8) + (\frac{1}{4}-\frac{1}{8})

                                            = 2 + (\frac{2-1}{8})

                                            = 2 + \frac{1}{8}

                                            = 2\frac{1}{8} inches

Therefore, Scruffy is 2\frac{1}{8} inches longer than Fluffy.

5 0
2 years ago
A researcher wants to test if the mean annual salary of all lawyers in a city is different from $110,000. A random sample of 50
KiRa [710]

Solution :

This is the two tailed test.

The null hypothesis and the alternate hypothesis is as :

Null hypothesis is $H_0:\mu=110000$

Alternate hypothesis is $H_0:\mu \neq110000$

$\overline x = 112000, \ \mu = 110000, \sigma = 16100, n =  50, \alpha = 0.02$

Therefore, the critical value of z is :

$z_{\alpha} = -2.33 \text{ and}\  2.33$

Now the test statics is :

$z=\frac{\frac{(\overline x - \mu)}{\sigma}}{\sqrt n}$

$z=\frac{\frac{(112000-110000)}{16100}}{\sqrt {50}}$

$z=0.87$

The test statics is 0.878

We see that it is a right tailed test.

$P(z > 0.878)=1-P(z

$P- \text{value}= \ 2 \times 0.19$

              = 0.3800

Thus , P-value > α

So we fail to reject the null hypothesis.

5 0
2 years ago
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