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Allisa [31]
3 years ago
8

What is the coefficient of the second term of the trinomial?

Mathematics
2 answers:
marin [14]3 years ago
7 0
The coefficient of the second term is 18.

What you do is you FOIL the terms:
(3x+3)(3x+3)\\ Multiply\ the\ first\ terms\ together:\\ 3x*3x=9x^{2}\\ Then\ the\ outer\ terms:\\ 3x*3=9x\\ Next,\ the\ inner\ terms:\\ 3x*3=9x\\ Finally,\ multiply\ the\ last\ terms:\\ 3*3=9\\ Putting\ the\ terms\ together:\\ 9x^{2}+9x+9x+9=9x^{2}+18x+9\\\\ Since\ (3x+3)^{2}=9x^{2}+Bx+9=9x^{2}+18x+9,\ then \ B=18.
pishuonlain [190]3 years ago
7 0
Answer:  " 18 " .
_______________________
Explanation:
_____________________
  (3x + 3)²
 
 =   (3x + 3) (3x + 3)  ;
 
 =  Using "FOIL" method:  "First, Outer, Inner, and Last" terms ;
_____________________________________________________
First terms:  3x* 3x = 9x² ;
Outer terms:  3x * 3 = 9x ;
Inner terms:  3 * 3x = 9x ;
Last terms:   3 * 3 = 9 ;
________________________________
   So,  we have:  " 9x² + 9x + 9x + 9" ;
______________________________
      Combine the "like forms" to simplify further:
_______________________________________
          The "like terms" are:  + 9x + 9x = 18x ; 
_______________________________________
 Rewrite the expression:  
_______________________________________
          " 9x²  + 18x +  9 ";
_________________________________________
We want to find the coefficient of the second term in the trinomial given:
_________________________________________
          " 9x² + <span /><em>B</em>x + 9 "  ; 
_________________________________________
The coefficient of the second term in this polynomial is: "<em>B</em>" ;
_________________________________________
                <em>B</em><em /> = 18 .
_________________________________________
The answer is:  " 18 " .
_________________________________________
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For what value of x is the rational expression below equal to zero x-4/(x+5)(x-1)
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4 0
3 years ago
Please help me if you know how to do this!
lukranit [14]

Question 21

Let's complete the square

y = 3x^2 + 6x + 5

y-5 = 3x^2 + 6x

y - 5 = 3(x^2 + 2x)

y - 5 = 3(x^2 + 2x + 1 - 1)

y - 5 = 3(x^2+2x+1) - 3

y - 5 = 3(x+1)^2 - 3

y = 3(x+1)^2 - 3 + 5

y = 3(x+1)^2 + 2

Answer: Choice D

============================================

Question 22

Through trial and error you should find that choice D is the answer

Basically you plug in each of the given answer choices and see which results in a true statement.

For instance, with choice A we have

y < -4(x+1)^2 - 3

-7 < -4(0+1)^2 - 3

-7 < -7

which is false, so we eliminate choice A

Choice D is the answer because

y < -4(x+1)^2 - 3

-9 < -4(-2+1)^2 - 3

-9 < -7

which is true since -9 is to the left of -7 on the number line.

============================================

Question 25

Answer: Choice B

Explanation:

The quantity (x-4)^2 is always positive regardless of what you pick for x. This is because we are squaring the (x-4). Squaring a negative leads to a positive. Eg: (-4)^2 = 16

Adding on a positive to (x-4)^2 makes the result even more positive. Therefore (x-4)^2 + 1 > 0 is true for any real number x.

Visually this means all solutions of y > (x-4)^2 + 1 reside in quadrants 1 and 2, which are above the x axis.

5 0
3 years ago
F(x) = 2x² + 8x Find f(-1)​
inysia [295]

Answer:

-6

Step-by-step explanation:

2(-1)^2 + 8*-1 = 2*1+8*-1=2-8=-6

8 0
3 years ago
Read 2 more answers
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