What is the coefficient of the second term of the trinomial?

Mathematics

2 answers:

marin [14]3 years ago

7 0

The coefficient of the second term is 18.

What you do is you FOIL the terms:
$(3x+3)(3x+3)\\ Multiply\ the\ first\ terms\ together:\\ 3x*3x=9x^{2}\\ Then\ the\ outer\ terms:\\ 3x*3=9x\\ Next,\ the\ inner\ terms:\\ 3x*3=9x\\ Finally,\ multiply\ the\ last\ terms:\\ 3*3=9\\ Putting\ the\ terms\ together:\\ 9x^{2}+9x+9x+9=9x^{2}+18x+9\\\\ Since\ (3x+3)^{2}=9x^{2}+Bx+9=9x^{2}+18x+9,\ then \ B=18.$

pishuonlain [190]3 years ago

7 0

Answer: " 18 " .
_______________________
Explanation:
_____________________
(3x + 3)²

= (3x + 3) (3x + 3) ;

= Using "FOIL" method: "First, Outer, Inner, and Last" terms ;
_____________________________________________________
First terms: 3x* 3x = 9x² ;
Outer terms: 3x * 3 = 9x ;
Inner terms: 3 * 3x = 9x ;
Last terms: 3 * 3 = 9 ;
________________________________
So, we have: " 9x² + 9x + 9x + 9" ;
______________________________
Combine the "like forms" to simplify further:
_______________________________________
The "like terms" are: + 9x + 9x = 18x ;
_______________________________________
Rewrite the expression:
_______________________________________
" 9x² + 18x + 9 ";
_________________________________________
We want to find the coefficient of the second term in the trinomial given:
_________________________________________
" 9x² + Bx + 9 " ;
_________________________________________
The coefficient of the second term in this polynomial is: "B" ;
_________________________________________
B = 18 .
_________________________________________
The answer is: " 18 " .
_________________________________________

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