∑x = 5 + 7 + 8 + 4 + 11 + 12 + 8 + 7 = 62
(∑x)^2 = 62^2 = 3,844
x bar = 62 / 8 = 7.75
∑x^2 = 25 + 49 + 64 + 16 + 121 + 144 + 64 + 49 = 522
∑y = 79 + 82 + 83 + 81+ 86 + 89 + 91 + 84 = 675
(∑y)^2 = 455,625
y bar = 675 / 8 = 84.375
∑y^2 = 6,241 + 6,724 + 6,889 + 6,561 + 7,396 + 7,921 + 8,281 + 7,056 = 57,069
∑xy = 395 + 574 + 664 + 324 + 946 + 1,068 + 728 + 588 = 5,287
r = (∑xy - n(x bar)(y bar)) / (sqrt(∑x^2 - n(x bar)^2) sqrt(∑y^2 - n(y bar)^2)) = (5,287 - 8(7.75)(84.375)) / (sqrt(522 - 8(7.75)^2) sqrt(57,069 - 8(84.375)^2)) = (5,287 - 5,231.25) / (sqrt(522 - 480.5) sqrt(57,069 - 56,953.125)) = 55.75 / (sqrt(41.5) sqrt(115.875)) = 55.75 / 69.3456 = 0.8039
Answer:
Step-by-step explanation:
t=C/ c
C=quantity in a cup
c=quantity in a teaspoon
Let's first define the variables:
x = width
300 - 2x = long
The area will be:
A = (x) * (300 - 2x)
A = 300x - 2x²
We look for the maximum area, for this, we derive:
A '= 300 - 4x
We match zero:
0 = 300 - 4x
x = 300/4 = 75
Therefore, the width is:
x = 75 feet
The length is:
300 - 2x = 300 - 2 (75) = 300-150
150 feet
Answer:
Part A:
The maximum area will be:
A = (150) * (75) = 11250 square feet
Part B:
The dimensions are:
Length = 150 feet
width = 75 feet
