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Digiron [165]
3 years ago
15

A box is known to hold exactly 250 cm3. Which side dimensions produce the most accurate measurement of the box?

Mathematics
1 answer:
My name is Ann [436]3 years ago
7 0

Answer:

A) 4.9 x 5.1 x 10.0

Step-by-step explanation:

4.9 x 5.1 x 10.0

4.9 x 5.1 x 10.0 = 249.90 cm3 is the closest to the true known value.

The other answers are more precise, but not as accurate. Accuracy is how close a measured value is to the actual or true value.

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Hector eats 10 ounces of candy in 5 days. A. How many pounds does he eat per day *
igomit [66]

Answer:

800

Step-by-step explanation:

Looked it up. also  16 times 10 times 5 = 800

5 0
3 years ago
Read 2 more answers
  A store that buys and sells used video games buys a game at a cost of ​$9 and sells it at a selling price of ​$12. Find the ma
d1i1m1o1n [39]

Answer:

a) markup = $3

b) markup as a percentage of cost is 33.3%

Step-by-step explanation:

<em>Markup</em>

... markup = selling price - cost

... = $12 - 9

... markup = $3

<em>Markup as a Percentage of Cost</em>

To find the percent markup, divide the markup by the reference value and multiply the ratio by 100%. The reference value for markup is usually cost price, but sometimes may be selling price.

... markup / cost × 100% = 3/9×100% = 33 1/3% ≈ 33.3%

_____

When the markup is figured as a percentage of selling price, the result is usually called <em>margin</em>. Some folks are not very careful in distinguishing markup from margin.

3 0
3 years ago
What is 10+9 let's see if u can guess it
postnew [5]
10 + 9 = 19 its simple math
7 0
3 years ago
True or false ???????????????please help
Dovator [93]
1  True   because 19^3  = 6859
2. False
3. True because 8000 ^1/3  can be written as 100^1/3 * 8^1/3
4 False 
5 True because they are both = 15

If you have a scientific calculator you can check these out yourself
7 0
4 years ago
The surface areas of two similar figures are given. The volume of the larger figure is given. Find the volume of the smaller fig
muminat

Answer:

The volume of smaller figure is 180 m³

Step-by-step explanation:

Consider the provided information.

The ratio of the surface areas is equal to the square of scale factor K.

let K₁ and K₂ is the scale factor

Thus \frac{k^2_1}{k^2_2} =\frac{S.A_1}{S.A_2}

Substitute the respective values as shown.

\frac{k^2_1}{k^2_2} =\frac{192}{1728}

\frac{k^2_1}{k^2_2} =\frac{1}{9}

\frac{k_1}{k_2} =\frac{1}{3}

It is given that the volume of larger figure is 4860 m³.

Let V₁ and V₂ is the volume of small and larger figure respectively.

The ratio of the volume is equal to the third power of scale factor K.

Thus \frac{k^3_1}{k^3_2} =\frac{V_1}{V_2}

Substitute the respective values as shown.

\frac{1^3}{3^3} =\frac{V_1}{4860}

\frac{1}{27} =\frac{V_1}{4860}

V_1=\frac{4860}{27}

V_1=180

Hence, the volume of smaller figure is 180 m³

3 0
3 years ago
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