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Allushta [10]
3 years ago
11

You play tennis with your friend every week. From all of the past games, you know that each game is independent and you estimate

that
you have a 60% chance of winning any one game. If you play two games against your friend next week, what is the probability that you lose
both of the games?
Mathematics
1 answer:
Murrr4er [49]3 years ago
8 0

Answer:

120%

Step-by-step explanation:

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Question
kondor19780726 [428]

Answer: r = 11

Step-by-step explanation:

We know that the point (-2, r) lies on the graph of:

2*x + y = 7.

Then, if we that point is on the graph of the equation, we can replace the values and we will have:

2*(-2) + r = 7

and now we solve this for r-

-4 + r = 7

r = 7 + 4 = 11

r = 11

6 0
3 years ago
If (k+1), 3k, (4k+2) are three consecutive terms of an AP then k = ?​
seropon [69]

The three consecutive terms in an AP are (k+1) ,3k and (4k+2)

We know that

If a,b,c are the three consecutive terms in an AP then b = (a+c)/2

now ,

Let a = k+1 , b = 3k and c = 4k+2

⇛3k = (k+1+4k+2)/2

⇛3k = (5k+3)/2

⇛2×3k = 5k+3

⇛6k = 5k+3

⇛ 6k-5k = 3

⇛ k = 3

The value of k = 3

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5 0
2 years ago
Suppose an amount of $10,000 is deposited into a bank account that pays 4% interest compounded four times a year. If there are n
In-s [12.5K]

Answer:

A=10,000(1+\frac{0.04}{4})^{4(5)}

Step-by-step explanation:

For a problem like this, we would use the compound interest formula:

A=P(1+\frac{r}{n} )^{nt}

<em>P = initial balance</em>

<em>r = interest rate (decimal)</em>

<em>n = number of times compounded annually</em>

<em>t = time</em>

<em />

First, lets change 4% into a decimal:

4% -> \frac{4}{100} -> 0.04

Since the interest is compounded 4 times a year, we will use 4 for <em>n</em>.

The equation is shown below:

A=10,000(1+\frac{0.04}{4})^{4(5)}

5 0
4 years ago
According to a survey, 10% of Americans are afraid to fly. Suppose 1100 Americans are sampled. a) What is the probability that 1
JulijaS [17]

Answer:

a) 14.46%

b) 0.00%

c) 1.54%

Step-by-step explanation:

According to the survey, 10% of Americans are afraid to fly.

This means p=0.10 and q=1-0.10=0.90.

If 1100 Americans are sampled, then the sample size is n=1100 .

The mean of the distribution is \mu=np.

This means \mu=1100\times 0.10=110

The standard deviation is \sigma=\sqrt{npq}

We substitute the values to get:

\sigma=\sqrt{1100\times 0.1\times 0.9}=9.95

a) We want to find the probability that 121 or more Americans in the survey are afraid to fly.

We first apply the continuity correction factor to get: P(X\ge121)=P(X\:>\:121-0.5)\\P(X\ge121)=P(X\:>\:120.5)

We now convert to Z-scores to get:

P(X\:>\:120.5)=P(z\:>\:\frac{120.5-110}{9.95})=1.06\\

From the standard normal distribution table P(z>1.06)=0.1446

As a percentage, the probability is 14.46%

b) We want to find the probability that 165 or more Americans in the survey are afraid to fly.

We apply the CCF to get:

P(X\ge165)=P(X\:>\:165-0.5)\\P(X\ge165)=P(X\:>\:164.5)

We convert to z-scores:

P(X\:>\:164.5)=P(z\:>\:\frac{164.5-110}{9.95})=5.48

From the normal distribution, P(z>164.5)=0

c)  First, 8% of 1100 is 88.

We want to find the probability that 88 or less Americans in the survey are afraid to fly.

We apply the CCF to get:

P(X\le88)=P(X\:

We convert to z-scores:

P(X\:

From the normal distribution, P(z>\:-2.16)=0.0154

As a percentage, we get 1.54%

3 0
4 years ago
What is 42 inches plus 2.5 feet plus 1.5 yards equal?
SVEN [57.7K]
The answer to the question is 8.2
4 0
3 years ago
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