Answer:
(w^2 - 4w + 16)
Step-by-step explanation:
Note that w^3 +64 is the sum of two perfect cubes, which are (w)^3 and (4)^3. The corresponding factors are (w + 4)(w^2 - 4w + 16).
Therefore,
(w^3 +64)/(4+ w) reduces as follows:
(w^3 +64)/(4+ w) (4 + w)(w^2 - 4w + 16)
--------------------------- = --------------------------------- = (w^2 - 4w + 16)
4 + w 4 + w
Answer:
x = 3.4
Step-by-step explanation:
recall that for a right angle with an internal angle θ,
cos θ = adjacent length / hypotenuse
in our case,
θ = 55 deg
adjacent length = x units
hypotenuse = 6 units
substitute these into the formula above
cos θ = adjacent length / hypotenuse
cos 55 = x / 6 (multiply both sides by 6)
x = 6 cos 55 (use calculator)
x = 3.4415
x = 3.4 (rounded to nearest tenth)
The legs are 5 inches long.
Use the Pythagorean theorem:
The length of the hypotenuse of the triangle is approximately 7 inches long.
162/(6(7-4)^2)
pemdas
parenthasees inner first
so 7-4 is forst
7-4=3
162/(6(3)^2)
then exponents
3^2=9
162/(6(9))
multiplication
6 times 9=54
162/(54)=3
