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guajiro [1.7K]
3 years ago
12

Que números primos son mayores que -6

Mathematics
1 answer:
kumpel [21]3 years ago
7 0
No sé, prueba 2,3,5,7,11,13....
Hay muchos números primos!
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You must be at least 42 inches tall to ride the bumper cars at an amusement park. Write an inequality that represents this situa
Anestetic [448]

Answer:

x is greater than or equal to 42 inches (I can't do the smybol for it)

Step-by-step explanation:

5 0
3 years ago
If x = 4, y = 3, z = -5, then evaluate: z - z + x - y
deff fn [24]
I got -15 as the answer, hope it works
7 0
3 years ago
Read 2 more answers
in the figure below trianglePQM and triangleQRP are right triangles. the measure of lineQM is 6 and the measure of lineQP is 8.
Kipish [7]

Answer:

Option 4 is correct. The length of PR is 6.4 units.

Step-by-step explanation:

From the given figure it is noticed that the triangle PQR and triangle MQR.

Let the length of PR be x.

Pythagoras formula

hypotenuse^2=base^2+perpendicular^2

Use pythagoras formula for triangle PQM.

PM^2=QM^2+PQ^2

PM^2=(6)^2+(8)^2

PM^2=36+64

PM^2=100

PM=10

The value of PM is 10. The length of PR is x, so the length of MR is (10-x).

Use pythagoras formula for triangle PQR.

PQ^2=QR^2+PR^2

(8)^2=QR^2+x^2

64-x^2=QR^2                   .....(1)

Use pythagoras formula for triangle MQR.

MQ^2=QR^2+MR^2

(6)^2=QR^2+(10-x)^2

36=QR^2+x^2-20x+100

36-x^2+20x-100=QR^2        .... (2)

From equation (1) and (2) we get

36-x^2+20x-100=64-x^2

20x-64=64

20x=128

x=6.4

Therefore length of PR is 6.4 units and option 4 is correct.

3 0
3 years ago
Two cargo ships are sailing a direct course into harbor. Ship A is 22 miles from harbor. Ship Bis sailing into harbor on a cours
s344n2d4d5 [400]

Answer:

The distance of ship B from the Harbor is 32.26 miles

Step-by-step explanation:

Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.

I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the <u>COSINE operator</u> to solve for the length of the course of ship B.

cos(x) = \frac{adjacent}{hypotenuse}

cos(47) = \frac{22miles}{hypotenuse} .... flip both fractions.

\frac{1}{cos(47)} = \frac{hypotenuse}{22miles} .... multiply both sides by 22

\frac{22mi}{cos(47)} = hypotenuse

32.26mi = hypotenuse = B

So the distance of ship B from the Harbor is 32.26 miles

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

3 0
3 years ago
What is the percent change from 1800 to 1926
Crank
The percentage change is 6.54%
You have to divide 1800÷1926, then multiply by 100 and you'd get 93.46, then subtract 100-93.46 which equals 6.54% :)
4 0
3 years ago
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