Find Slope -5,3 and 7,8

Mathematics

2 answers:

hodyreva [135]3 years ago

6 0

Answer:

5/12.

Step-by-step explanation:

Slope = (y2 - y1) / (x2 - x1) where the 2 points are (x1, y1) and (x2, y2).

So here it is:

(8 - 3)/ (7 - (-5))

= 5/12.

34kurt3 years ago

3 0

Answer:

5/12

Step-by-step explanation:

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The picture explains it

Vsevolod [243]

Answer:

Step-by-step explanation:

you know that if one line is perpendicular to another line, and another line is perpendicular to that line, they are all perpendicular (90). so, all corners are right angles. that means that angle AGD is 90. so, if you know 30, then subtract 30 from 90 and you get that angle AGF is 60. then, because angle AGF and angle EGB are vertical angles, they are congruent, so x is 60.

3 0

3 years ago

Plz help I have no idea how to answer it

saveliy_v [14]

5. Answer: see explanation

<u>Step-by-step explanation:</u>

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0 and x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0 then p = -4m and q = 3m²

3p² = 3(-4m)² 16q = 16(3m²)

= 3(16m²) = 48m²

= 48m²

3p² = 48m² = 16q ⇒ 3p² = 16q

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6. Answer: 8 or 18

<u>Step-by-step explanation:</u>

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

Bigger non-shaded Δ: L = 12-x, w = 10 ⇒ $A = \dfrac{10(12-x)}{2}$
Smaller non-shaded Δ: L = x, w = x ⇒ $A=\dfrac{x(x)}{2}$

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

$\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}$