Hi,
"Four plus six" is the verbal expression.
Hope this helps.
r3t40
Answer: P^2 - 10p + 24 = 0
Step-by-step explanation:
Given that a company’s weekly revenue, in thousands, is modeled by the equation
R = -p2 + 14p,
where p is the price of the product it makes. The company is considering hiring an outside source to distribute its products, which will cost the company 4p + 24 thousand dollars per week.
If the company want to break even, the cost of hiring distributors will be equal to the revenue per week.
Therefore,
-P^2 + 14p = 4p + 24
Collect the like terms
-P^2 + 14p - 4p - 24 = 0
-P^2 + 10p - 24 = 0
Multiply all by minus sign
P^2 - 10p + 24 = 0
From my research, the image below belongs to the question. From what is seen in the image, there are 2 arcs already drawn with respect to the new vertex. The third arc corresponds to the point where the line DM is made. This line is similar to line BC. So at the point where the second and third arcs would meet, it would be a point similar to a point on line AB.
To find W⊥, you can use the Gram-Schmidt process using the usual inner-product and the given 5 independent set of vectors.
<span>Define projection of v on u as </span>
<span>p(u,v)=u*(u.v)/(u.u) </span>
<span>we need to proceed and determine u1...u5 as: </span>
<span>u1=w1 </span>
<span>u2=w2-p(u1,w2) </span>
<span>u3=w3-p(u1,w3)-p(u2,w3) </span>
<span>u4=w4-p(u1,w4)-p(u2,w4)-p(u3,w4) </span>
<span>u5=w5-p(u4,w5)-p(u2,w5)-p(u3,w5)-p(u4,w5) </span>
<span>so that u1...u5 will be the new basis of an orthogonal set of inner space. </span>
<span>However, the given set of vectors is not independent, since </span>
<span>w1+w2=w3, </span>
<span>therefore an orthogonal basis cannot be found. </span>
Answer:
A. 2 acute and 1 right angle.
