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Ivanshal [37]
4 years ago
9

Vgc

class="latex-formula">
step by step​
Mathematics
2 answers:
dem82 [27]4 years ago
5 0

Answer:

4x+28

Step-by-step explanation:

Distributive property is a(b+c)=ab+ac

4(x+7)

4*x=4x

4(x)=4*7

4*7=28

4x+28, which is our answer.

frez [133]4 years ago
4 0

\text{Hey there!}

\text{In order for you to solve for this equation, you need to distribute.}

\text{The formula is: a(b + c) = a(b) + a(c) = ab + ac}

\text{Keep that method in mind.}

\text{4(x + 7)}\\\\\text{4(x) + 4(7)}\\\\\text{4(x) = 4x}\\\\\ 4(7) = 28\\\\\boxed{\boxed{\text{\bf{Answer: 4x + 28}}}}\bf\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{LoveYourselfFirst:)}

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lubasha [3.4K]
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{a}^{3}  + {b}^{3} = (a + b)( {a}^{2 }  - ab +  {b}^{2} )


EXPLANATION

To find the expression that is equivalent to
{a}^{3}  + {b}^{3}
we must first expand
{(a + b)}^{3}
Then we rearrange to find the required expression.


So let's get started.


{(a + b)}^{3}  = (a + b) {(a + b)}^{2}

We expand the parenthesis on the right hand side to get,



{(a + b)}^{3}  = (a + b) ( {a}^{2} + 2ab +  {b}^{2}  )



We expand again to obtain,

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Let us group the cubed terms on the right hand side to get,

{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3 {a}^{2}b + 3a {b}^{2}




{(a + b)}^{3}  =  {a}^{3}   +  {b}^{3}  + 3ab (a+ b)





We make the cubed terms the subject,

{(a + b)}^{3}  - 3ab (a+ b) =  {a}^{3}   +  {b}^{3}

We factor to get,


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We expand the bracket on the left hand side to get,

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We finally simplify to get,

(a + b)( {a}^{2}   - ab +  {b}^{2}  ) =  {a}^{3}   +  {b}^{3}
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