<u><em>The total number of red counters that are in the box is; 728 red counters</em></u>
- We are told that the box contains 1079 counters.
Let the number of white counters be x.
Let the number of red counters be y.
Let the number of black counters be z.
Thus;
z:x = 2:7
Thus; 2x/7 = z
Also, we are given;
x:y = 3:8
Thus;
8x/3 = y
- Since total number in the box is 1079,then;
x + y + z = 1079
x + (8x/3) + (2x/7) = 1079
Multiply through by 21 to get;
21x + 56x + 6x = 22659
83x = 22659
x = 22659/83
x = 273
2x/7 = z
Thus; z = 2 × 273/7
z = 78
8x/3 = y
y = 8 × 273/3
y = 728
273 white counters
728 red counters
78 black counters.
Read more at; brainly.com/question/11712611
The answer is: reduction
Explanation: since there are prime number markings on the smaller shape, that is the second version. In other words, the bigger shape was the original because there are no prime markings (‘) on it and to turn into the smaller shape, it had to shrink (reduce)
25 students got 2 chaperones
so 1 will get 2/25
and thus 8 will get 2/25×8 = 0.64 chaperone
but is it possible?? No chaperone can not be in decimal so at least 1 is required !!
Answer:
Step-by-step explanation:
Divide both sides by -3:
