Question

jamie wants to put tiles on the walls and floor of his room( but not on the ceiling). The length of his room is 10 feet,the width of his rooms is 14 feet , and the height is 12 feet. If each tile is 1 foot long and 1 foot wide how many tiles will jamie need ?

Answer 1

Answer:

716 tiles needed.

Step-by-step explanation:

The parameters of a room given in the question are

Length = 10 feet

Width = 14 feet

Height = 12 feet

and Jamie wants to put the tiles on walls and the floor of his room.

Dimensions of each tile

Length = 1 feet

width = 1 feet

Surface area of walls and floor = 4 walls + floor = 4(Area of one wall) + area of floor

= 2(Length×height + width×height) + (length×width)

= 2(10×12 + 14×12) + (10×14) = 2(120+168) + 140 = 2×288 + 140 = 576 +140 = 716

Now total number of tiles required = Total area to be covered/area of one tile

Number of tiles = 716/1 = 716  

Therefore 716 tiles needed by Jamie.

Answer 2

Answer:

716 tiles are required by Jamie.

Step-by-step explanation:

We are given the following information in the question:

Dimensions of room:

Length of room = 10 feet

Width of room = 14 feet

Height of room = 12 feet

Dimensions of tile:

Length = 1 feet

Width = 1 feet

Area of 1 tile =

$\text{Length}\times \text{Width}\\= 1\times 1\\= 1 \text{ square feet}$

Area of room to be covered by tiles =

$\text{Area of base} + \text{Area of 4 walls}\\= (\text{Length}\times \text{Breadth}) + 2\times \text{Height}\times (\text{Length + Breadth})\\=10\times 14 + (2\times 12\times (10 + 14))\\=140 + 576\\= 716\text{ square feet}$

Number of tiles required =

$\displaystyle\frac{\text{Area t be covered}}{\text{Area of 1 tile}} = \frac{716}{1} = 716\text{ tiles}$

Thus, 716 tiles are required by Jamie.