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sveta [45]
2 years ago
9

Find the area of a rectangle with a length of (4x)^3/2 and a width of 12x^3/4

Mathematics
1 answer:
mojhsa [17]2 years ago
4 0

\bf Area = length\cdot width\implies A = (4x)^{\frac{3}{2}}\cdot 12x^{\frac{3}{4}}\implies A=4^{\frac{3}{2}}x^{\frac{3}{2}}\cdot 12x^{\frac{3}{4}} \\\\\\ A=(2^2)^{\frac{3}{2}}x^{\frac{3}{2}}\cdot 12x^{\frac{3}{4}}\implies A=2^3x^{\frac{3}{2}}\cdot 12x^{\frac{3}{4}}\implies A=8x^{\frac{3}{2}}\cdot 12x^{\frac{3}{4}} \\\\\\ A=(8\cdot 12)x^{\frac{3}{2}}\cdot x^{\frac{3}{4}}\implies A=96x^{\frac{3}{2}+\frac{3}{4}}\implies A=96x^{\frac{6+3}{4}}\implies A=96x^{\frac{9}{4}}

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Answer:

Ok I don't know waht you mean but the answer is

Step-by-step explanation:

Answer:

x=3/2±(√11)2

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Find the Solution for

2x^22−6x+10=0

using the Quadratic Formula where

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x=(−b±√(b^2−4ac))/2a

x=(−(−6)±√((−6)2−4(2)(10)))2(2)

x=(6±√(36−80))/4

x=(6±√−44)/4

The discriminant b^2−4ac<0

so, there are two complex roots.

Simplify the Radical:

x=(6±2√11 i)/4

x=6/4±(2√11 i)4

Simplify fractions and/or signs:

x=3/2±(√11)2

which becomes

x=1.5+1.65831i

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