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Harman [31]
3 years ago
15

Find the center and radius of circle and graph it

%2B2%29%5E%7B2%7D%20%3D%209" id="TexFormula1" title="(x-4)^{2} +( y +2)^{2} = 9" alt="(x-4)^{2} +( y +2)^{2} = 9" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
sergeinik [125]3 years ago
3 0

Answer:

centre = (4,-2)

radius = 3

Step-by-step explanation:

The centre-radius form of the circle equation is in the format

(x – h)² + (y – k)² = r²,

with the centre being at the point (h, k) and the radius being "r"

Given in the question an expression which can be write as

<h3> (x – 4)² + (y – (-2))² = 3²</h3>

So, by translating we can say that

centre = (4,-2)

and

radius = 3

 

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Quickly please lol!!!!
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Answer:

C

Step-by-step explanation:

Plug in -2 instead of X you get Y = 15

then plug in 3 instead of X you get Y = 0

5 0
3 years ago
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Find the number of terms in this polynomial. 7g7 + 10g4 – 6g3 + 3g2 - g​
Gnoma [55]

Answer:

If you have more than 4 terms you say polynomial with the certain number of terms you have. So the answer to this is polynomial with 5 terms.

Hope this helps.

7 0
3 years ago
Andrew read a 320-page novel by reading the same number of pages each day for 5 days. Write and solve a multiplication equation
kolbaska11 [484]
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7 0
3 years ago
Find c, yenvelope(x,t), and ycarrier(x,t). express your answer in terms of a, k1, k2, x, t, ω1, and ω2. separate the three parts
steposvetlana [31]

Answer:

C,Y_{envelope}(x,t), Y_{carrier}(x,t)=2A, \cos ((k_1-k_2)x/2-(\omega_1 -\omega_2)t / 2 ) , \sin ((k_1+k_2)x / 2 - (\omega_1 +\omega_2)t / 2 )

Step-by-step explanation:

Given

Y_1(x,t)=A \sin(K_1x- \omega _1 t)\\\\Y_2(x,t)=A \sin(K_2x- \omega _2 t)

using a trigonometrical identity

sin p + sin q = 2 sin ( p+q/2) cos ( p-q/2)

and here the condition is

the choice is in between sinax and cosax

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so we get using above equation

C,Y_{envelope}(x,t), Y_{carrier}(x,t)=2A, \cos ((k_1-k_2)x/2-(\omega_1 -\omega_2)t / 2 ) , \sin ((k_1+k_2)x / 2 - (\omega_1 +\omega_2)t / 2 )

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4 years ago
What is the length of the hypotenuse of the triangle??
Ede4ka [16]

Answer:

65

Step-by-step explanation:

33² + 56² = 4225

Square root of 4225 = 65

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