Answer:
(6,6) only goes with Line 2
(3,4) goes with neither
(7,2) goes with both
Step-by-step explanation:
Ok to decide if a point is on a line you plug it in. If you get the same thing on both sides, then that point is on that line. If you don't get the same thing on both sides, then that point is not on that line.
Test (6,6) for -5x+6y=-23.
(x,y)=(6,6) gives us
-5x+6y=-23
-5(6)+6(6)=-23
-30+36=-23
6=-23
So (6,6) is not on -5x+6y=-23.
Test (6,6) for y=-4x+30
(x,y)=(6,6) give us
y=-4x+30
6=-4(6)+30
6=-24+30
6=6
So (6,6) is on y=-4x+30.
Test (3,4) for -5x+6y=-23.
(x,y)=(3,4) gives us
-5x+6y=-23
-5(3)+6(4)=-23
-15+24=-23
9=-23
So (3,4) is not on -5x+6y=-23.
Test (3,4) for y=-4x+30.
(x,y)=(3,4) gives us
y=-4x+30
4=-4(3)+30
4=-12+30
4=18
So (3,4) is not on y=-4x+30.
Test (7,2) for -5x+6y=-23.
(x,y)=(7,2) gives us
-5x+6y=-23
-5(7)+6(2)=-23
-35+12=-23
-23=-23
So (7,2) is on -5x+6u=-23.
Test (7,2) for y=-4x+30.
(x,y)=(7,2) gives us
y=-4x+30
2=-4(7)+30
2=-28+30
2=2
So (7,2) is on y=-4x+30
(x,y) Line 1 Line 2 Both Neither
(6,6) *
(3,4) *
(7,2) *
(6,6) only goes with Line 2
(3,4) goes with neither
(7,2) goes with both
All I saw there was area so just multiply 10.2 and 17 which is 173.4
Answer:
12(−12m+38)
Step-by-step explanation:
12(−12m+38)
Answer:
Stratified design with color of paper as the blocks
Step-by-step explanation:
The experimental design that this question uses is the stratified design with color of paper as the blocks
A stratified design is one where the population has been divided into strata that are homogeneous. A good number of participants would then be picked for each of the stratum. The homogeneous strata are also known as the blocks and here in this question we have color of paper as the block here.
The students are of different school levels, elementary, high school and middle school. Each of these levels have 100 students. The students in each levels are halved and each half is randomly assigned information on either a white paper or a blue paper.
Answer:
The last choice: 25. 12 / pi
Explanation:
The relationship b
