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4 years ago

If 8 cakes cost £4,then how much do 3 cakes cost?

Mathematics

2 answers:

Inessa [10]4 years ago

8 0

8 = £4
1 = £0.50
3 = 3 × £0.50
3 = £1.50

Pani-rosa [81]4 years ago

3 0

Its £1 . 50
u work out how much 1 is
to do this u do 4 / 8 which gives u 50p
then multiply it by 3 which gives u the answer
hope this helps u

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Please look at picture

dezoksy [38]

Answer:

This question is so bad but it is most likely 25% or 0. this has no context in the question

Step-by-step explanation:

6 0

3 years ago

22/7 pi and 6 inches

Evgen [1.6K]

Answer:

264/7 37.71

Step-by-step explanation:

22/7×6(2)

=>22/7×12

=>37.71 or 264/7

6 0

3 years ago

textRequest reports that adults 18–24 years old send and receive 128 texts every day. Suppose we take a sample of 25–34 year old

Butoxors [25]

Testing the hypothesis, we have that:

The null hypothesis is: $H_0: \mu = 128$

The alternative hypothesis is: $H_1: \mu \neq 128$

b) The p-value of the test is of 0.1212.

c) Since the p-value of the test is of 0.1212 > 0.05, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

d) Since |z| = 1.55 < 1.96, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

Item a:

At the null hypothesis, we test if the mean is the same, that is, of 128 texts every day, hence:

$H_0: \mu = 128$

At the alternative hypothesis, we test if the mean is different, that is, different of 128 texts every day, hence:

$H_1: \mu \neq 128$

Item b:

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

$\sigma$ is the standard deviation of the population.

n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 118.6, \mu = 128, \sigma = 33.17, n = 30$

Hence, the value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{118.6 - 128}{\frac{33.17}{\sqrt{30}}}$

$z = -1.55$

Since we have a two-tailed test, as we are testing if the mean is different of a value, the p-value is P(|z| < 1.55), which is 2 multiplied by the p-value of z = -1.55.

Looking at the z-table, z = -1.55 has a p-value of 0.0606

2(0.0606) = 0.1212

The p-value of the test is of 0.1212.

Item c:

Since the p-value of the test is of 0.1212 > 0.05, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

Item d:

Using a z-distribution calculator, the critical value for a two-tailed test with 95% confidence level is |z| = 1.96.

Since |z| = 1.55 < 1.96, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

A similar problem is given at brainly.com/question/25369247

4 0

3 years ago

For a telephone call from New York City to Los Angeles, a telephone company charges $1.05 for the first three minutes and $0.25

Serggg [28]

c because m is the number of minutes over 3 so you would multiply that by 0.25 and add 1.05 altogether.

1.05 is what under 3 minutes is. 0.25 times m(the number of minutes over 3) and add them.

1.05+0.25

6 0

3 years ago

Write each number in standard form

Rina8888 [55]

Answer:

math.way is great for this

Step-by-step explanation:

i hope that helps

8 0

4 years ago