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zaharov [31]
4 years ago
12

Someone please help me

Mathematics
1 answer:
Black_prince [1.1K]4 years ago
8 0

Answer:

720 degrees

Step-by-step explanation:

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How did business leaders in the late nineteenth century utilize vertical integration? a. They maintained control of the raw mate
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Business leaders in the late nineteenth century utilized vertical integration by maintaining control of production and distribution of their products.

Answer: Option C

<u>Explanation: </u>

Vertical integration is a competitive strategy that gives the company full control over one or more stages of product production or distribution. Rockefeller tirelessly tried to take full control of business 'oil refinery'. While other business people were flooding the area in search of quick fortune, Rockefeller was thinking of destroying his rivals and creating a real monopoly in the refining industry.

Looking for even more control, Rockefeller saw the benefits of organizing the transportation to his products. Then, he began to develop his business through vertical integration, in which the company analyses all aspects of the product life cycle, from raw material extraction, through the production process, to the final delivery of the product.

Other industrialists quickly followed, including Gustavus Swift, who at the end of the 19th century used vertical integration to dominate the American meat packaging industry.

3 0
3 years ago
Help help help please !!!!
docker41 [41]

Answer:

D. 17

Step-by-step explanation:

If PR equals 34, to get PT divide 34 by 2 since it's half of PR.

6 0
3 years ago
Will the shape shrink or enlarge?
aleksklad [387]
The shape will shrink
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3 years ago
Name the quadrilaterals that have four equal angles.
Alex73 [517]
B. square, rectangle
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Read 2 more answers
Samples of 20 parts from a metal punching process are selected every hour. Typically, 1% of the parts require rework. Let X deno
Roman55 [17]

Answer:

a) P(X>np+3\sqrt{np(1-p)}=0.017

b) P(x>1)=0.190

c) P(Y>1)=0.651

Step-by-step explanation:

This a binomial experiment where success is denoted by parts that need rework.

X ∼ B(n, p); n = 20; p = 0.01

The expected value of X is: E(X) = np =20×0.01= 0.2

The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,

The standard deviation SD(X)= \sqrt{0.198} ≈ 0.445

a) P(X>np+3\sqrt{np(1-p)}=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)

Probability function is given by:

\frac{n!}{x!(n-x)!} *p^x*(1-p)^{(n-x)}

P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - \frac{20!}{1!(20-1)!} *(0.01)^{1}*(1-0.01)^{(20-1)}-\frac{20!}{0!(20-0)!} *(0.01)^{0}*(1-0.01)^{(20-0)}

P(X≥2)=1-0.165-0.818=0.017

b) p=0.04

P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - \frac{20!}{0!(20-1)!} *(0.04)^{1}*(1-0.04)^{(20-1)} - \frac{20!}{0!(20-0)!} *(0.04)^{0}*(1-0.04)^{(20-0)}

P(x>1)= 1 - 0.368 - 0.442=0.190

c) In this case we consider p=0.19 (Probability that X exceeds 1)

In this experiment Y is the number of hours and n= 5 hours.

Then, we check the probability in each hour:

P(Y>1)=1- P(Y=0)

P(Y=0)=\frac{5!}{0!(5-0)!} *(0.19)^{0}*(1-0.19)^{(5-0)}=0.349

P(Y>1)=1-0.349=0.651

3 0
3 years ago
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