Answer:
R=22
Step-by-step explanation:
180-44= 136
136÷2= 68
90-68= 22
180 is angle of the straight line. 44 is subtracted to get angle of only the triangle on the left which is 136. 136 is then divided by 2 since the remaining two angles are equal and you'll get 68. R is part of a right-angled triangle (90°) subtract 68 from that and you will get 22
Answer:
H0 : μ = 0.5
H0 : μ > 0.5
Kindly check explanation
Step-by-step explanation:
H0 : μ = 0.5
H0 : μ > 0.5
We perform a right tailed test :
Sample proportion :
Number of games won, x = 142
Number of games, n = 250
phat = x / n = 142 / 250 = 0.568 = 56.8%
Yes, it is consistent
Test statistic :
(phat - p) * √Phat(1-Phat)/n
1 -Phat = 1 -0.568 = 0.432
(0.568 - 0.5) /√(0.568*0.432)/250
0.068 / 0.0313289
= 2.17
The Pvalue using the z test statistic :
Pvalue = 0.015
α = 0.03
Since ;
Pvalue < α ; We reject the null and conclude that teams tend to win more often when they play at home.
Answer:
The length of DF is 15
Step-by-step explanation:
Since the two lines are equal, which is given by the markings on the triangle, then you can set the two lengths equal and find x.
7x - 13 = 3x + 3
4x - 13 = 3
4x = 16
x = 4
Now that we know x = 4, we can plug into the DF length to find its amount.
DF = 7x - 13
DF = 7(4) - 13
DF = 28 - 13
DF = 15
Answer:
a)
Therefore to compare this data effectively using the rates per driver is better off like for people who do not smoke their rate will be = 59 / 452 = 13.1% while for smokers of 61+ times = 50 / 156 = 32.1% and this rate will show clearly tat more accidents where caused by people who smoked 51+ times hence it should be used for graphical representation
b) attached below
Step-by-step explanation:
A) A useful graph is must compare rates rather than counts of accidents in the four marijuana use classes
Using the rates on a graph is better for reference like saying; that 50 crashes were caused by those who smoke 51+ times and 59 crashes is caused by those who never smoke this statistics makes it seem like smoking has no effect on the amount of accidents
Therefore to compare this data effectively using the rates per driver is better off like for people who do not smoke their rate will be = 59 / 452 = 13.1% while for smokers of 61+ times = 50 / 156 = 32.1% and this rate will show clearly tat more accidents where caused by people who smoked 51+ times hence it should be used for graphical representation
B) accident rate for Non-smokers
= (59/452) * 100 = 13.05
accident rate for smokers between 1-10 times
= ( 36/ 229 ) * 100 = 15.72
accidents rate for smokers between 11 - 50 times
= ( 15/50 ) * 100 = 21.42
accidents rate for smokers 51+
= ( 50 / 156 ) * 100 = 32.05
attached below is the required graph