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Travka [436]
2 years ago
8

What is the slope of the line represented by the equation y = 4/5x - 3?

Mathematics
1 answer:
ololo11 [35]2 years ago
5 0

Answer:

i think c but not positive

Step-by-step explanation:

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Scarlet has $85 to spend at the pet store. She is definitely buying a catfish for $12, a rainbowfish for $13, and a betta fish f
ikadub [295]

Subtract the total of the 3 fish she is buying from the amount of money she has:

85 - (12 + 13 + 14) = 85 - 39 = 46

She has $46 to spend on crabs.

Divide the amount she has to spend by the price on one crab:

46 / 8 = 5.75

Since it isn't a whole number you need to round down, since she cant buy 0.75 of a crab.

She has enough money to buy 5 crabs.

7 0
2 years ago
What is the solution of 3x+9<15
Zolol [24]

Answer:

Third one

Step-by-step explanation:

<u>Two </u>things to solve      3x+9 <= 15

                                        3x <= 6

                                         <u> x <= 2</u>

      <u>   and</u>   - (3x+ 9) <= 15

                  - 3x - 9 <= 15

                   - 3x <= 24

                      3x >= -24

                     <u>   x > = - 8 </u>

<u />

<u />

<u>s o   -8 <= x <= 2 </u>

3 0
1 year ago
PLEASE HELP!!!! The equation shows how the total cost of members-only speaker series is related to the number of events attended
ad-work [718]

Answer:

149 is what i think it is

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
) a, p and d are n×n matrices. check the true statements below:
BigorU [14]
A. False. Consider the identity matrix, which is diagonalizable (it's already diagonal) but all its eigenvalues are the same (1).

b. True. Suppose \mathbf P is the matrix of the eigenvectors of \mathbf A, and \mathbf D is the diagonal matrix of the eigenvalues of \mathbf A:


\mathbf P=\begin{bmatrix}\mathbf v_1&\cdots&\mathbf v_n\end{bmatrix}

\mathbf D=\begin{bmatrix}\lambda_1&&\\&\ddots&\\&&\lambda_n\end{bmatrix}

Then

\mathbf{AP}=\begin{bmatrix}\mathbf{Av}_1&\cdots&\mathbf{Av}_n\end{bmatrix}=\begin{bmatrix}\lambda_1\mathbf v_1&\cdots&\lambda_n\mathbf v_n\end{bmatrix}=\mathbf{PD}

In other words, the columns of \mathbf{AP} are \mathbf{Av}_i, which are identically \lambda_i\mathbf v_i, and these are the columns of \mathbf{PD}.

c. False. A counterexample is the matrix

\begin{bmatrix}1&1\\0&1\end{bmatrix}

which is nonsingular, but it has only one eigenvalue.

d. False. Consider the matrix

\begin{bmatrix}0&1\\0&0\end{bmatrix}

with eigenvalue \lambda=0 and eigenvector \begin{bmatrix}k&0\end{bmatrix}^\top, where k\in\mathbb R. But the matrix can't be diagonalized.
7 0
3 years ago
Determine the range of the function. (0,2) (2,4) (4,6) (6, 8) (8, 10)
Nikolay [14]
The given points, <span>(0,2) (2,4) (4,6) (6, 8) (8, 10), represent a relationship / function.

The range includes all of the y-values:  {2, 4, 6, 8, 10}, which can also be expressed as [2,10].  This is equivalent to answer C.</span>
8 0
3 years ago
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