Question

What is the total surface area of this square pyramid?

Answer 1

Answer:

The total surface area of this square pyramid is $297\ mm^{2}$

Step-by-step explanation:

we know that

The surface area of a square pyramid is equal to

$SA=b^{2} +4[\frac{1}{2}(b)(h)]$

we have

$b=9\ mm$ ----> the length side of the square base

$h=12\ mm$ ----> the height of the triangular faces

substitute the values

$SA=9^{2} +4[\frac{1}{2}(9)(12)]=297\ mm^{2}$