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Rom4ik [11]
3 years ago
10

What is the mean of the data set below: 0 1 1 2 5 6

Mathematics
1 answer:
Nuetrik [128]3 years ago
4 0
"Mean" is another way of saying average.
To find the average/mean, add up all the numbers and then divide by the amount of numbers that are in the data set.

Step 1: Add the numbers.
0 + 1 + 1 + 2 + 5 + 6
= 15

Step 2: Divide the sum by the amount of numbers in the set.
There are 6 numbers in the data set.
Their sum is 15.
Divide 15 by 6.
15 / 6
= 2.5

Answer:
The mean, also known as average, of this data set is 2.5.

Hope this helps!
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Lenz father is paying for a $20 meal. He has a 15%-off coupon on his meal. After the discount, a 7% sales tax is applied. How mu
loris [4]

Answer:$18.19

Step-by-step explanation:

5 0
3 years ago
Algebra 1, solve each inequality. w + 3 > 9
QveST [7]

Move all terms not containing w to the right side of the inequality.

Inequality Form:

w>6

Interval Notation:

(6, ∞)

5 0
4 years ago
Read 2 more answers
Decide if the following scenario involves a permutation or combination. Then find the number of possibilities.
deff fn [24]

Given:

The batting order for nine players on a team with 11 people.

To find:

The number of possibilities for the given scenario.

Solution:

First, we need to select 9 players from 11 people, it involves combination, i.e. ^{11}C_9.

Second, we need to arrange the order of 9 selected players, it involves permutation, i.e., ^9P_9.

The number of possibilities for the given scenario is:

\text{Possibilities}=^{11}C_9\times ^9P_9

\text{Possibilities}=\dfrac{11!}{(11-9)!9!}\times \dfrac{9!}{(9-9)!}

\text{Possibilities}=\dfrac{11\times 10\times 9!}{2!9!}\times \dfrac{9!}{0!}

\text{Possibilities}=\dfrac{110}{2\times 1}\times \dfrac{9\times 8\times 7\times 6\times 5\times 4\times 3\times 2\times 1}{1}

\text{Possibilities}=55\times 362880

\text{Possibilities}=19958400

Therefore, the following scenario involves both permutation and combination, and the number of possibilities is 19958400.

6 0
3 years ago
A, b, c and d are positive integers, such that a+b+ ab = 76, c+d+ cd = 54. Find (a+b+c+d)·a·b·c·d.
lutik1710 [3]

Notice that

(1 + <em>x</em>)(1 + <em>y</em>) = 1 + <em>x</em> + <em>y</em> + <em>x y</em>

So we can add 1 to both sides of both equations, and we use the property above to get

<em>a</em> + <em>b</em> + <em>a b</em> = 76  ==>  (1 + <em>a</em>)(1 + <em>b</em>) = 77

and

<em>c</em> + <em>d</em> + <em>c d</em> = 54  ==>  (1 + <em>c</em>)(1 + <em>d</em>) = 55

Now, 77 = 7*11 and 55 = 5*11, so we get

<em>a</em> + 1 = 7  ==>  <em>a</em> = 6

<em>b</em> + 1 = 11  ==>  <em>b</em> = 10

(or the other way around, since the given relations are symmetric)

and

<em>c</em> + 1 = 5  ==>  <em>c</em> = 4

<em>d</em> + 1 = 11  ==>  <em>d</em> = 10

Now substitute these values into the desired quantity:

(<em>a</em> + <em>b</em> + <em>c</em> + <em>d</em>) <em>a</em> <em>b</em> <em>c</em> <em>d</em> = 72,000

6 0
3 years ago
A car traveled on the highway at 65 miles per hour for 45 minutes. What distance did the car travel?
daser333 [38]

i think its 52 miles.

the fraction of the time is 4/5 which is .8 so

65 * .8 = 52

i hope this helps :)

3 0
3 years ago
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