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Rus_ich [418]
3 years ago
15

What is the 75th term of the arithmetic sequence -1, 5, 11

Mathematics
1 answer:
lana [24]3 years ago
7 0

Answer:

75th term = 443

Step-by-step explanation:

a_{n}=a_{1}+d(n-1) \\a_{n}=-1+6(n-1) \\a_{75}=-1+6(75-1) \\a_{75}=-1+6(74)\\a_{75}=-1+444\\a_{75}=443 \\\\

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Answer:

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Step-by-step explanation:

When we have a set of N different elements, the total number of permutations is given by:

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Particularly, if out of these N elements, there are a given element that is repeated K times, then the permutations of these K elements actually do not add new unique permutations, then in that case the total number of unique permutations is:

P = N!/K!

And if we have another element that is repeated L times, then with the same reasoning than above, the total number of unique permutations is:

P = N!/(K!*L!)

Now, we have the set:

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So we have a set of 9 letters, then:

N = 9

And, the letter S is repeated 3 times

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Then, using the above notation, we can define:

K = 3

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The total number of permutations is then:

P = \frac{9!}{3!*3!}  = \frac{9*8*7*6*5*4*3*2*1}{3*2*1*3*2*1} = \frac{9*8*7*6*5*4}{3*2*1} = 2,520

So there are 2,520 unique permutations.

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Step-by-step explanation:

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