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Fittoniya [83]
3 years ago
9

Graph the system of equations. Then determine whether it has no solution, one

Mathematics
1 answer:
Nikitich [7]3 years ago
7 0

Answer:

One solution: (6, -1)

Step-by-step explanation:

I have attached the work to your problem below.

Please see the attachment.

I hope this helps.

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P is the set of even numbers that are less than 11
ivanzaharov [21]

Is there a restriction that the set must be positive? or whole numbers? Because negative numbers can be even, which makes your set an infinite list of numbers.

Natural numbers: P = {2, 4, 6, 8, 10}

Whole numbers: P = {0, 2, 4, 6, 8, 10}

All real numbers: P = {2n ;n ≤ 5}

6 0
3 years ago
For each equation determine whether it is linear.
Elan Coil [88]
The only linear equation is choice d
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What is a Cartesian plan?
nataly862011 [7]
I'm assuming you mean Cartesian plane. It is the same as a coordinate plane. There are two perpendicular lines with an x (horizontal) and y (vertical) axis. 
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3 years ago
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Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.
Lelechka [254]

Answer:

1) \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}} = 32

Step-by-step explanation:

1) \frac{(-2)^{-5}}{(-2)^{-10}}

Solving using exponent rule: a^{-m}=\frac{1}{a^m}

\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32

So, \frac{(-2)^{-5}}{(-2)^{-10}}=-32

2) 2^{-1}.2^{-4}

Using the exponent rule: a^m.a^n=a^{m+n}

We have:

2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}

We also know that: a^{-m}=\frac{1}{a^m}

Using this rule:

2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}

So, 2^{-1}.2^{-4} = \frac{1}{32}

3) (-\frac{1}{2} )^3.(-\frac{1}{2} )^2

Solving:

(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}

So, (-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}

4) \frac{2}{2^{-4}}

We know that: a^{-m}=\frac{1}{a^m}

\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32

So, \frac{2}{2^{-4}} = 32

3 0
3 years ago
1. What is the next term of the arithmetic sequence 6, 10, 14, 18
givi [52]
It’s 22 (add 6 after every term)
8 0
3 years ago
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