The average of the five consecutive numbers ending with b in discuss when expressed in terms of a is; Choice D; a+3.
<h3>What is the average of five consecutive integers ending with b?</h3>
First, since it was given in the task content that the average of six positive consecutive odd integers starting with a is equal to b, it therefore follows that;
(a+a+2+a+4+a+6+a+8+a+10)/6 = b
6b=6a+30
b=a+5
Also, let the average of the consecutive intergers ending with b be denoted by; x.
(b+b-1+b-2+b-3+b-4)/5 = x
=(5b-10)/5
=b–2
The average, x=b – 2 (where b = a-5)
Ultimately, the value of the required average is; = a+5-2 = a+3.
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Both sides would be the same, so set them to equal ans solve for x.
3x+4 = 2x +7
Subtract 4 from each side:
3x = 2x +3
Subtract 2x from each side:
x = 3
The answer is X = 3.
Answer:
$721.55
Step-by-step explanation:
658.95*1.095=721.55
Answer:
The first blank is $640.30
The second blank is 670
Step-by-step explanation:
This is really up to you. Also you Didn’t provide the assignment so this is impossible to answer, I can put anything in there. Just think about what you did and answer the questions yourself.
