Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is:
Answer:
Of(7) = f(1) + 24
Step-by-step explanation:
Since this Arithmetic Sequence can be written recursively as a function, then we can write the whole sequence, by adding the common difference to the previous function. So writing it as an Arithmetic formula is (placing an example, with a common difference of 4 units):
We have the following expression:
(27a ^ 3-1) / (9a ^ 2-6a + 1)
Rewriting we have:
(27a ^ 3-1) / (9a ^ 2-6a + 1)
(27a ^ 3-1) / ((3a-1) * (3a-1))
We exclude the values that make the denominator zero:
3a-1 = 0
a = 1/3
Answer:
a valid exclusion for the algebraic fraction is:
c. a ≠ 1/3
I'm not exactly sure what kind of answer you are looking for but angle L would also be 72 degrees. This is because 36 (K) + 72 (J) = 108 and a triangle's angles must add up to 180 so 180 - 108 = 72 (L) . This also makes sense because it is an isosceles triangle so two of the angles must be the same because two of the sides are the same length.
