Question

PLEASE HELP ASAP!!!

Answer 1

Answer:

C. (a, b)

Step-by-step explanation:

The formula of a midpoint:

$M\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

We have A(0, 0) and C(2a, 2b). Substitute:

$x=\dfrac{0+2a}{2}=\dfrac{2a}{2}=a\\\\y=\dfrac{2b+0}{2}=\dfrac{2b}{2}=b$

M(a, b)

Answer 2

Answer:

Choice C is correct.

Step-by-step explanation:

The  formula to find mid-point of a line segment is:

M= ($x_{1}+x_{2}$/2,$y_{1} +y_{2}$/2)

where  ($x_{1} ,y_{1}$) and ($x_{2} ,y_{2}$) are end-points  of a line segment.

we have to find mid-point of AC.

A is located at the center of xy-graph.

hence, A($x_{1} ,y_{1}$) is given as (0,0) and C($x_{2} ,y_{2}$) is given as (2a,2b).

put above values in the formula of mid-point formula:

M=(0+2a/2,0+2b)

M=(2a/2,2b/2)

M=(a,b) is mid-point of AC.