Answer:
✔︎
༄❁༄❁༄❁༄❁༄
![a=8\\b=2\\c=?\\d=?\\e=5](https://tex.z-dn.net/?f=a%3D8%5C%5Cb%3D2%5C%5Cc%3D%3F%5C%5Cd%3D%3F%5C%5Ce%3D5)
![Using~ Pythagorean ~theorem:](https://tex.z-dn.net/?f=Using~%20Pythagorean%20~theorem%3A)
![c^2=a^2+b^2](https://tex.z-dn.net/?f=c%5E2%3Da%5E2%2Bb%5E2)
![c^2=(8)^2+(2)^2](https://tex.z-dn.net/?f=c%5E2%3D%288%29%5E2%2B%282%29%5E2)
![\sqrt{c^2} =\sqrt{68}](https://tex.z-dn.net/?f=%5Csqrt%7Bc%5E2%7D%20%3D%5Csqrt%7B68%7D)
![c=\sqrt{68} ~or~2\sqrt{17}](https://tex.z-dn.net/?f=c%3D%5Csqrt%7B68%7D%20~or~2%5Csqrt%7B17%7D)
»»---------------------►
![d^2=c^2+e^2](https://tex.z-dn.net/?f=d%5E2%3Dc%5E2%2Be%5E2)
![d^2=(2\sqrt{17})^2+(5)^2](https://tex.z-dn.net/?f=d%5E2%3D%282%5Csqrt%7B17%7D%29%5E2%2B%285%29%5E2)
![d^2=68+25](https://tex.z-dn.net/?f=d%5E2%3D68%2B25)
![\sqrt{d^2} =\sqrt{93}](https://tex.z-dn.net/?f=%5Csqrt%7Bd%5E2%7D%20%3D%5Csqrt%7B93%7D)
![d=\sqrt{93} ~or~9.6](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B93%7D%20~or~9.6)
![So, your~ answer ~is ~9.6](https://tex.z-dn.net/?f=So%2C%20your~%20answer%20~is%20~9.6)
✧⋄⋆⋅⋆⋄✧⋄⋆⋅⋆⋄✧⋄⋆⋅⋆⋄✧⋄⋆⋅⋆⋄✧
hope it helps...
have a great day!!
Answer:
the probability would be a 1/3 or a 1/6 chance i think
Answer:
-1.5 and 1.5
I don't have those sings but -1.5 goes on the first box and 1.5 goes on the second one
Answer: ![\frac{\sqrt{77}}{22}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B77%7D%7D%7B22%7D)
Step-by-step explanation:
Given:
![\frac{\sqrt{7}}{2\sqrt{11}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B7%7D%7D%7B2%5Csqrt%7B11%7D%7D)
Since the denominator is a surd , to simplify , all we need do is to rationalize
That is
×![\frac{\sqrt{11}}{\sqrt{11}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B11%7D%7D%7B%5Csqrt%7B11%7D%7D)
⇒ ![\frac{\sqrt{77}}{2(11)}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B77%7D%7D%7B2%2811%29%7D)
⇒
which is the simplified form of ![\frac{\sqrt{7}}{2\sqrt{11}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B7%7D%7D%7B2%5Csqrt%7B11%7D%7D)