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kow [346]
3 years ago
6

Im Bored:( Somebody send me a message

Mathematics
2 answers:
dedylja [7]3 years ago
5 0
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Veseljchak [2.6K]3 years ago
4 0

Answer:

ok

Step-by-step explanation:

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The ratio of losses to wins for Kyle's team is 3 to 2. If the team had played the same number of games, but had won twice as man
Fiesta28 [93]

Answer: The new ratio will be 1/4

Explanation: The initial ratio of losses to wins is 3 to 2. If we sum the numer of losses and wins 3 + 2 = 5 games, that means they loss 3 out of 5 games , and they win 2 out of 5 games.

So if they had won twice as many of the games, that is 2*2=4. And since the number of games is the same ( 5 ), then they would have won 4 games and loss only 1.

So the new ratio of losses to wins will be 1 to 4, or expressed in a fraction: 1/4

4 0
3 years ago
Read 2 more answers
Why does a logarithmic equation sometimes have an extraneous solution?
jonny [76]

The main reason behind this is using properties of logarithm .

like

when solving

  • log_2(x+2)+log_2(x-3)=3

There you use multiplication property and make addition to multiplication then you get extraneous solution because in plenty of cases they occur

like

  • (-2)²=(2)²

But

  • -2≠2

Same happens in case of logarithm

6 0
2 years ago
Read 2 more answers
Evaluate the expression when m=4<br> m^2-9m-5
enyata [817]

Answer:-25

Step-by-step explanation:

simplify

3 0
3 years ago
Read 2 more answers
Which is greater, 35% of 60 or 30% of 80?
lara [203]
35% of 60 = (35/100)*60 = 0.35 * 60 = 21

30% of 80 = (30/100)*80 = 0.30 * 80 = 24

24 is greater than 21.

30% of 80 is greater.

8 0
3 years ago
Read 2 more answers
Determine if the following system of equations has no solutions 4x+3y= -8 -8x-6y= 16
cupoosta [38]

\begin{cases} 4x+3y=-8\\\\ -8x-6y=16 \end{cases}~\hspace{10em} \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

4x+3y=-8\implies 3y=-4x-8\implies y=\cfrac{-4x-8}{3}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{4}{3}} x-\cfrac{8}{3} \\\\[-0.35em] ~\dotfill\\\\ -8x-6y=16\implies -6y=8x+16\implies y=\cfrac{8x+16}{-6} \\\\\\ y=\cfrac{8}{-6}x+\cfrac{16}{-6}\implies y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{4}{3}} x-\cfrac{8}{3}

one simple way to tell if both equations do ever meet or have a solution is by checking their slope, notice in this case the slopes are the same for both, meaning the lines are parallel lines, however, notice both equations are really the same, namely the 2nd equation is really the 1st one in disguise.

since both equations are equal, their graph will be of one line pancaked on top of the other, and the solutions is where they meet, hell, they meet everywhere since one is on top of the other, so infinitely many solutions.

3 0
2 years ago
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