Answer:
Shopper spend $3 on Apples, $4 on Grapes and $3.5 on Oranges
Step-by-step explanation:
Cost of one pound of Apple = $2x
Cost of one pound of Grapes = $(6x-5)
Cost of one pound of Oranges = $(x+2)
A shopper purchases one pound each of apples, grapes, and oranges and spends $10.50.
It can be written as: 
We need to find how much the shopper spend on each fruit.
First we need to find value of x by solving equation

Solving:

The value of x is: x=1.5
Now finding cost of one pound each fruit by putting x=1.5
Cost of one pound of Apple = $2x = 2(1.5) = $3
Cost of one pound of Grapes = $(6x-5) = (6(1.5)-5)= $4
Cost of one pound of Oranges = $(x+2)=(1.5+2)=$3.5
So,
Cost of one pound of Apple = $3
Cost of one pound of Grapes = $4
Cost of one pound of Oranges = $3.5
So, shopper spend $3 on apples, $4 on Grapes and $3.5 on Oranges
Answer:
5
Step-by-step explanation:
Hello!
To find the area of a rectangular prism you do 2(lw + lh + wh)
Put in the values
2(9 * 2 + 9 * 6 + 2 * 6)
2(18 + 54 + 12)
2(84)
2 * 84 = 168
The answer is 168 cubic inches
Hope this helps!
Answer:
2125m or 2km or 125m
Step-by-step explanation:
If you like my answer than please mark me brainliest thanks
Answer:
The correct option is (b).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

The confidence interval for population mean can be computed using either the <em>z</em>-interval or <em>t</em>-interval.
The <em>t</em>-interval is used if the following conditions are satisfied:
- The population standard deviation is not known
- The sample size is large enough
- The population from which the sample is selected is normally distributed.
For computing a (1 - <em>α</em>)% confidence interval for population mean , it is necessary for the population to normally distributed if the sample selected is small, i.e.<em>n</em> < 30, because only then the sampling distribution of sample mean will be approximated by the normal distribution.
In this case the sample size is, <em>n</em> = 28 < 30.
Also it is provided that the systolic blood pressure is known to have a skewed distribution.
Since the sample is small and the population is not normally distributed, the sampling distribution of sample mean will not be approximated by the normal distribution.
Thus, no conclusion can be drawn from the 90% confidence interval for the mean systolic blood pressure.
The correct option is (b).