PLEASE HELP ASAP ALGEBRA 2 QUESTION
1 answer:
Let x represent the gallons of water that is 10% salt. Let y represent the gallons of water that is 25% salt. Now, write the system of equations: x + y = 10 .10x +.25y = 0.20 • 10 1) To make the system easier to solve, multiply all the terms in .10x +.25y = 0.20(10) by 100 to make them integers. 10x + 25y = 20 • 10 10x + 25y = 200 2) Solve for x. x + y = 10 x = 10 - y 3) Substitute x with 10 - y in the other equation. 10(10 - y) + 25y = 200 100 - 10y + 25y = 200 Combine like terms. 100 + 15y = 200 Subtract 100 from both sides. 15y = 100 y = 20/3 or 6 2/3 4) Now that we have the numerical value of y, solve for the value of x by substituting once more. a) x + y = 10 x + 20/3 = 10 or x + 6 2/3 = 10 (either equation is fine) x = 10/3 or x = 3 1/3 The manager should combine 3 1/3 (3.33) gallons of 10% salt water and 6 2/3 (6.67) gallons of 25% salt water. 5) Always check the answers to make sure. a) x + y = 10 3 1/3 + 6 2/3 = 10 9 3/3 = 10 10 = 10 b) .10x +.25y = 0.20 • 10 .10(3 1/3) +.25(6 2/3) = 0.20 • 10 1/3 + 5/3 = 2 6/3 = 2 2 = 2
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Step-by-step explanation:
a number r added to 3.7 is 3.7 + r
New expression 3.7 + r should be less than 1.2 --->
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