There are 5 groups of 3 in the number 15, so 15/3=5
Answer:
2(4a+b-2)
Step-by-step explanation:
All you need to do is factor out 2 from the expression. (sorry if this is wrong)
Answer:
A) 68.33%
B) (234, 298)
Step-by-step explanation:
We have that the mean is 266 days (m) and the standard deviation is 16 days (sd), so we are asked:
A. P (250 x < 282)
P ((x1 - m) / sd < x < (x2 - m) / sd)
P ((250 - 266) / 16 < x < (282 - 266) / 16)
P (- 1 < z < 1)
P (z < 1) - P (-1 < z)
If we look in the normal distribution table we have to:
P (-1 < z) = 0.1587
P (z < 1) = 0.8413
replacing
0.8413 - 0.1587 = 0.6833
The percentage of pregnancies last between 250 and 282 days is 68.33%
B. We apply the experimental formula of 68-95-99.7
For middle 95% it is:
(m - 2 * sd, m + 2 * sd)
Thus,
m - 2 * sd <x <m + 2 * sd
we replace
266 - 2 * 16 <x <266 + 2 * 16
234 <x <298
That is, the interval would be (234, 298)
Answer:
Midpoint of AB = (0 + 2a / 2 , 0 + 0 / 2) = (2a / 2 , 0 / 2) = (a,0)
x coordinate of point c = a
N = (0 + a / 2 , 0 + b / 2) = (a / 2 , b / 2)
M = ( 2a + a / 2 , 0 + b / 2) = (3a / 2 , b / 2)
MA = √(3a / 2 - 0)² + b / 2 - 0)²
= √(3a / 2 )² + (b / 2) = 9a² / 4 + b² / 4
NB = √(a / 2 - 2a)² + (b / 2 - 0 )²
= √( a / 2 - 4a / 2)² + (b / 2 - 0)²
= √(-3a / 2)² + (b / 2)² = √9a² / 4 + b² / 4
Step-by-step explanation:
I tried my best hope its correct :0