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Mathematics

2 answers:

MArishka [77]3 years ago

8 0

This a right triangle shown above

scoray [572]3 years ago

6 0

Answer:

<h2>obtuse</h2>

Step-by-step explanation:

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Which equation is true about the measure of the angles of the triangle?the measure of angle prq is equal to 100 degreesthe measu

harkovskaia [24]

I believe this question is missing an image. However, I will just tell how how to solve such question and you can apply this solution to the triangle you have.

In any given triangle, the sum of the measure of the three angles must be equal to 180 degrees.
Therefore, for a triangle pqr:
measure angle pqr + measure angle prq + measure angle rqp = 180 degrees

If you have one angle given, then the sum of the other two angles will be equal to 180 - measure of the given angle.

If you have two angles given, then the measure of the third angle will be equal to 180 - the sum of the other two angles.

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Aubrey's car used 4 gallons to travel 100 miles. How many miles can the car go on one gallon of gas?

yarga [219]

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Step-by-step explanation:

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A College Alcohol Study has interviewed random samples of students at four-year colleges. In the most recent study, 494 of 1000

Vinil7 [7]

Answer:

The 95% confidence interval for the difference between the proportion of women who drink alcohol and the proportion of men who drink alcohol is (-0.102, -0.014) or (-10.2%, -1.4%).

Step-by-step explanation:

We want to calculate the bounds of a 95% confidence interval of the difference between proportions.

For a 95% CI, the critical value for z is z=1.96.

The sample 1 (women), of size n1=1000 has a proportion of p1=0.494.

$p_1=X_1/n_1=494/1000=0.494$

The sample 2 (men), of size n2=1000 has a proportion of p2=0.552.

$p_2=X_2/n_2=552/1000=0.552$

The difference between proportions is (p1-p2)=-0.058.

$p_d=p_1-p_2=0.494-0.552=-0.058$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{494+552}{1000+1000}=\dfrac{1046}{2000}=0.523$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.523*0.477}{1000}+\dfrac{0.523*0.477}{1000}}\\\\\\s_{p1-p2}=\sqrt{0.000249+0.000249}=\sqrt{0.000499}=0.022$