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Juliette [100K]
3 years ago
5

How to find the prime factorization of 65

Mathematics
2 answers:
ddd [48]3 years ago
8 0
5 x 13
65 x 1
This isn't the only factorization, there's also the 65 and 1.
jek_recluse [69]3 years ago
3 0
The prime factorization of 65 is 5 x 13.<span> Five and 13 are not just the only prime factors of 65, but they are also the only factors of this number other than 1 and 65. A prime number is one that has no factors other than itself and 1.</span>
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a leaf hangs from a branch 12 feet in the air. it falls to the ground at a rate of 0.25 feet per second. which graph could repre
Kipish [7]
For this case we have an equation of the form:
 h (t) = (1/2) * (a) * (t ^ 2) + v0 * t + h0&#10;
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 h0: initial height
 v0: initial speed
 a: acceleration
 Substituting values we have:
 h (t) = (1/2) * (- 32) * (t ^ 2) + 0.25 * t + 12&#10;
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 h (t) = -16t ^ 2 + 0.25 * t + 12&#10;
 Note: see attached image
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h (t) = -16t ^ 2 + 0.25 * t + 12

7 0
3 years ago
26. If x:3 = 12:x, calculate the positive value of x.​
nydimaria [60]

Answer:

Answer ::+-6

Step-by-step explanation:

x:3=12:x

or, x/3 = 12/x

Doing cross multiplication,

x^2=36

Putting sqare root on both sides,

x= sqrt. 36

x= +- 6

Therefore x=+-6.

6 0
3 years ago
Read 2 more answers
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Harlamova29_29 [7]

Answer:

y=-2x-2

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8 0
3 years ago
Which of the numbers below are greater than 5/2
aleksandrvk [35]

Answer:

6/2

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
The term "freshman 15" refers to the claim that college students typically gain 15lbs during freshman year at college. Assume th
Viefleur [7K]

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

<h3>What is Probability ?</h3>

Probability is defined as the likeliness of an event to happen.

Let X be a random variable that shows the term "freshman 15" that claims that students typically gain 15lb during their freshman year at college.

It is given that

X follows is a normal distribution with a mean of 2.1 lb (μ) and a standard deviation (σ)  of 10.8 lb.

Population Mean (μ) = 2.1

Population Standard Deviation (σ) = 10.8

We need to compute Pr(X≥15). The corresponding z-value needed to be computed is:

\rm Z_{lower} = \dfrac{ X_1 -\mu }{\sigma}\\\\Z_{lower} = \dfrac{ 15-2.1 }{10.8}\\\\\\Z_{lower} = 1.19

Then the probability is given as

\rm Pr(X \geq 16 ) = Pr (\dfrac{X -21}{10.8} \geq \dfrac{15-21}{10.8})\\\\= Pr (Z \geq \dfrac{15-2.1}{10.8}\\\\= Pr (Z\geq 1.19)\\\\ = 0.1162

Pr(X≥15)=0.1162. (11.6%)

The probability that a randomly selected male college student gains 15 lb or more during their freshman year is 11.6%

To know more about Probability

brainly.com/question/11234923

#SPJ1

3 0
2 years ago
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