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UkoKoshka [18]
3 years ago
7

PLEASE HELP ME NOW!!

Mathematics
2 answers:
Alex Ar [27]3 years ago
8 0
<h2>Hello!</h2>

The answer is:

The correct answer is the first option.

(x-4)^{2}=4+-2\sqrt{7}

<h2>Why?</h2>

To solve the problem, we must remember the following square root property:

\sqrt{ab}=\sqrt{a}\sqrt{b}

So,

We are given the expression:

(x-4)^{2}=28

Now, isolating we have:

First, applying square root to both sides of the equation in order to simplify the quadratic term, we have:

\sqrt{(x-4)^{2} }=\sqrt{28}\\(x-4)=\sqrt{4*7}\\\\x=4+-(\sqrt{4}*\sqrt{7})\\\\x=4+-2\sqrt{7}

Hence, the correct answer is the first option.

(x-4)^{2}=4+-2\sqrt{7}

Have a nice day!

puteri [66]3 years ago
4 0

Answer:

x=4+-2\sqrt{7}

Step-by-step explanation:

To solve, we need to take square root of both sides first:

(x-4)^2=28\\\sqrt{(x-4)^2} =+-\sqrt{28} \\x-4=+-\sqrt{28}

Now we use the property of radical shown below to simplify square root of 28:

Property:  \sqrt{x*y}=\sqrt{x} \sqrt{y}

Now, we have:

x-4=+-\sqrt{28}\\x-4=+-\sqrt{4*7}\\x-4=+-\sqrt{4}\sqrt{7}\\x-4=+-2\sqrt{7}

Now we take 4 to the other side and isolate x:

x-4=+-2\sqrt{7} \\x=4+-2\sqrt{7}

first answer choice is right.

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