Differentiate:
-5×2(xe^x^2)y-5e^x^2dy/dx=1
-5e^x^2(2xy+y´)=1
When x=-5, y=0:
-5e²⁵y´=1, so y´(-5)=-eˉ²⁵/5
Answer:
see explanation
Step-by-step explanation:
Given the 3 equations
3x + 5y + 5z = 1 → (1)
x - 2y = 5 → (2)
2x + 4y = 11 → (3)
Use (2) and (3) to solve for x and y
Multiply (2) by 2
2x - 4y = 10 → (4)
Add (3) and (4) term by term
4x = 21 ( divide both sides by 4 )
x = 
Substitute this value of x into (3)
2 ×
+ 4y = 11
+ 4y = 11 ( subtract
from both sides )
4y =
( divide both sides by 4 )
y = 
Substitute the values of x and y into (1) and solve for z
3 ×
+ 5 ×
+ 5z = 1
+
+ 5z = 1
+ 5z = 1 ( subtract
from both sides )
5z = -
( divide both sides by 5 )
z = - 
Solution is
x =
, y =
, z = - 
Answer:
Using trigonometric ratio:


From the given statement:
and sin < 0
⇒
lies in the 3rd quadrant.
then;

Using trigonometry identities:
Substitute the given values we have;

Since, sin < 0
⇒
now, find
:

Substitute the given values we have;

Therefore, the exact value of:
(a)

(b)

Answer:
0.0032
Step-by-step explanation:
We need to compute
by the help of third-degree Taylor polynomial that is expanded around at x = 0.
Given :
< e < 3
Therefore, the Taylor's Error Bound formula is given by :
, where 



Therefore, |Error| ≤ 0.0032