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alina1380 [7]
3 years ago
12

What is the quotient when (10n^2-37n-12) is divided by (n-4)?

Mathematics
1 answer:
Papessa [141]3 years ago
7 0

I used synthetic division to determine the quotient.  Dividing by n-4 in long div. is equivalent to div. by 4 in synth. div.:

   __________________

4 /   10       -37         -12

                  40          12

 -----------------------------------

     10          3            0

Since there's no remainder, the quotient is 10x+3, which is obtained using the coefficients shown at the bottom above.

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Help needed: Solve for x. Round to the nearest tenth, if necessary.
Nookie1986 [14]

Answer:

x = 24.1

Step-by-step explanation:

From the question given above, the following data were obtained:

Angle θ = 15°

Adjacent = 90

Opposite = x =?

The value of x can be obtained by using Tan ratio as shown below:

Tan θ = Opposite / Adjacent

Tan 15 = x / 90

Cross multiply

x = 90 × Tan 15

x = 24.1

Therefore, the value of x is 24.1

7 0
2 years ago
The figure shows two similar triangles:
nasty-shy [4]

Answer:

An exterior angle of a triangle is equal to the sum of the two remote

Step-by-step explanation:

2 a b c. 13. 10 z. 169 100 z. 269 z z. 269 16.4. +. = +. = +. = = = ≈. 3 – 4 – 5 x6 x6 x6 ... x 12. = = = = w y z x.

3 0
2 years ago
What are the zeros of the function g(x) = (x + 6) (x – 4)(x + 2) ?
vitfil [10]

9514 1404 393

Answer:

  x in {-6, -2, 4}

Step-by-step explanation:

The zero product rule tells you that a product will be zero if and only if one of the factors is zero. These binomial factors are zero when x has a value that is opposite the constant of the binomial.

  x +6 = 0   ⇒   x = -6

  x -4 = 0   ⇒   x = 4

  x +2 = 0   ⇒   x = -2

The zeros of the function are the x-values -6, -2, and 4.

5 0
3 years ago
Solve the equation for x, where x is a real number (5 points): <br> -2x^2 + 5x - 10 = 3
KatRina [158]
Subtract 3 from both sides so that the equation becomes -2x^2 + 5x - 13 = 0.
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
                                      x = [ -b ± √(b^2 - 4ac) ] / (2a)
                                      x = [ -5 ± √((5)^2 - 4(-2)(-13)) ] / ( 2(-2) )
                                      x = [-5 ± √(25 - (104) ) ] / ( -4 )
                                      x = [-5 ± √(-79) ] / ( -4)
Since √-79 is nonreal, the answer to this question is that there are no real solutions.
3 0
3 years ago
Please help with this one
tino4ka555 [31]

The answer will be A-1188 in²

3 0
2 years ago
Read 2 more answers
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