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Juli2301 [7.4K]
4 years ago
12

What common base can be used to rewrite each side of the equation 2^(x+3)-3=5

Mathematics
2 answers:
ryzh [129]4 years ago
8 0
We are given with the equation <span>2^(x+3)-3=5 and is asked in the prooblem to determine the common base of each side of the equation. we transpose first 3 to the other side making it 8. 8 is equal to 2^3 which makes the common base then equal to 2.</span>
marin [14]4 years ago
6 0

Answer:

2

Step-by-step explanation:

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Sarah made 12 more free throws than Connie. How many free throws did Connie make if Sarah made 72?
Annette [7]
Connie made 60 throws and Sarah made 72.
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4 years ago
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Pythagorean theorem: find the perimeter
denis-greek [22]
The answer is 5
Explanation:
We need to use the Pythagorean,
a^2 + b^2 = c^2
Where c is the hypotenuse
We can fill in spots now 12^2 + b^2 = 13^2
And then we solve 144 + b^2 = 169
Next we get b^2 alone
169-144=25
So we get b^2=25
For the final step you have to find the square root of 25 to get b alone which is 5
3 0
3 years ago
A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2
Yuliya22 [10]

A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.

Answer: The correct option is B) about 34%

Proof:

We have to find P(4.2

To find P(4.2, we need to use z score formula:

When x = 4.2, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{4.2-5.1}{0.9}=\frac{-0.9}{0.9}=-1

When x = 5.1, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{5.1-5.1}{0.9}=0

Therefore, we have to find P(-1

Using the standard normal table, we have:

P(-1= P(z

                               =0.50-0.1587

                               =0.3413 or 34.13%

                               = 34% approximately

Therefore, the percent of data between 4.2 and 5.1 is about 34%

7 0
4 years ago
One day at a supermarket, 258 fruits were sold in the morning, and 5/6 of the number of fruits sold in the morning were sold in
astra-53 [7]

Answer:

258 fruits.

Step-by-step explanation:

We have been given that one day at a supermarket, 258 fruits were sold in the morning, and 5/6 of the number of fruits sold in the morning were sold in the afternoon.

So the fruits sold in the afternoon will be 5/6 of 258.

\text{The number of fruits sold in afternoon}=\frac{5}{6}\times 258

\text{The number of fruits sold in afternoon}=5\times 43

\text{The number of fruits sold in afternoon}=215.

Further, we are told that the number of fruits sold in the next afternoon increased by 20% compared to the number of fruits sold in the afternoon the previous day.

So the number of fruits sold in the next afternoon will be:

\text{The number of fruits sold in next afternoon}=215+(\frac{20}{100}\times 215)

\text{The number of fruits sold in next afternoon}=215+(0.20\times 215)

\text{The number of fruits sold in next afternoon}=215+43

\text{The number of fruits sold in next afternoon}=258

Therefore, 258 fruits were sold in the afternoon the next day.

4 0
3 years ago
Help me solve this please, im really bad at stuff like this
omeli [17]

Answer:

given

Step-by-step explanation:

5 0
3 years ago
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