Answer:
The 99% confidence interval estimate of the percentage of girls born is (86.04%, 93.96%). Considering the actual percentage of girls born is close to 50%, the percentage increased considerably with this method, which means that it appears effective.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
In the study 380 babies were born, and 342 of them were girls.
This means that 
99% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
As percentages:
0.8604*100% = 86.04%.
0.9396*100% = 93.96%.
The 99% confidence interval estimate of the percentage of girls born is (86.04%, 93.96%). Considering the actual percentage of girls born is close to 50%, the percentage increased considerably with this method, which means that it appears effective.
Answer:
$3.07
Step-by-step explanation:
22.2/6=3.7
hope this helps!
Answer:
3 not sure if you saw it Amazing the following statements best describes the role of yourself and God bless you and take care for you guys to paperwork
For the first figure, the geometric figure used in the construction that is shown is the intersection of the angle bisectors of the triangle is the center of the inscribed circle.
For the second figure, the construction of the above figure in the circle represents how to find the intersection of the perpendicular bisectors of triangle ABC.
For the third figure, the statement that is demonstrated in the in line P intersecting line m perpendicularly is the set of points equidistant from the endpoints of a line segment is the perpendicular bisector of the segment.
The answer to the question is
