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Aliun [14]
2 years ago
8

Write an equation of a polynomial with the given characteristics: a quadratic function has x -intercepts of -3 and 1, and a y-in

tercept of (0,9).
Mathematics
2 answers:
fredd [130]2 years ago
5 0

Answer:

f(x) = -3(x+3)(x-1)

Step-by-step explanation:

x = -3 & 1; f(x) = 9

f(x) = a(x-r1)(x-r2)

f(0) = a(x-r1)(x-r2) = 9; 9 = a(0-(-3))(0-1)

9 = a(3)(-1); 9 = a(-3)

a = -3

f(x) = -3(x+3)(x-1)

skelet666 [1.2K]2 years ago
4 0

Answer:

f(x) = -3x^2 - 6x + 9.

Step-by-step explanation:

As the x intercepts are - 3 and 1 we can write it as:

f(x) = a(x - 1)(x + 3)    where a is a constant to be found.

As the - intercept is at (0, 9),  x =0 when f(x) = 9 so we can also write:

a( 0 - 1)(0 + 3) = 9

(-1)(3)a = 9

a = 9 / -3

= -3.

So the equation is f(x) = -3(x - 1)(x + 3)

In expanded form it is

-3(x^2 + 2x - 3)

= -3x^2 - 6x + 9.

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Does anyone know this? I’m really stuck
S_A_V [24]

<em>p = 21</em>

Step-by-step explanation:

When you have a midsegment, the base is going to be two times as large as the midsegment. You can find the midsegment if you multiply it by two and set it equal to the base. I have attached a photo below that may help you.

This is the equation we will be using.

2(p-13)=p-5

Now let's solve! Let's start by distributing the 2 by what's in the parentheses.

2p-26=p-5

Subtract p from both sides.

p-26=-5

Add 26 to both sides.

<u>p = 21</u>

7 0
3 years ago
Read 2 more answers
(5,-5) and y = 3/2x +3Whats the equation of the line in slope intercept form
statuscvo [17]

Step-by-step explanation:

let (5,-5) =(x1,y1)

from eqn y=3/2x+3

slope (m)=3/2

now,

eqn in slope intercept form is;

(y-y1)=m (x-x1)

  • (y-5)=3/2 (x+5)
  • 2 (y-5)=3 (x+5)
  • 2y-10=3x+15
  • 3x-2y+25=0 is required eqn
4 0
3 years ago
English
asambeis [7]

Answer:

38.25 units.

Step-by-step explanation:

The trapezoid is given with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)

When given vertices ( x1, y1), (x2, y2)

We use the formula:

√(x2 - x1)² + (y2 - y1)² to find the length of the sides of the Trapezoid

Side QR: Q(8, 8), R(14, 16)

= √(x2 - x1)² + (y2 - y1)²

= √(14 - 8)² + (16 - 8)²

= √6² + 8²

= √36 + 64

= √100

= 10 units

Side RS: R(14, 16), S(20, 16)

= √(x2 - x1)² + (y2 - y1)²

= √(20 - 14)² + (16 - 16)²

= √6² + 0²

= √36

= 6 units

Side ST : S(20, 16), T(22, 8)

= √(x2 - x1)² + (y2 - y1)²

= √(22 - 20)² + ( 8 - 16)²

= √2² + (-8)²

= √4 + 64

= √68

= 8.2462112512

≈ nearest hundredth = 8.25 units

Side QT, Q(8, 8), T(22, 8)

= √(x2 - x1)² + (y2 - y1)²

= √(22 - 8)² + (8 - 8)²

= √14² + 0²

= √196

= 14 units

The Perimeter of a Trapezoid is the sum of all it's sides.

P = QR + RS + ST + QT

P = (10 + 6 + 14 + 8.25) units

P = 38.25 units

Therefore, the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8) is 38.25units.

3 0
3 years ago
150 grams of fertilizer is required for a land area of 6 square meters.
Dahasolnce [82]
If 150g of fertilizer can cover 6 sq m of land then, 25 g of fertilizer can cover 1 sq m of land;
a)
For 13 sq m of land we need 25g*13
325g
b)
850g/25g=amount of land
34 sq m
3 0
3 years ago
-1/3+-5/6<br> 4+12/6<br> 3/7 divided by -2/5
frutty [35]

Answer:

6.02 i think

Step-by-step explanation:

5 0
3 years ago
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